Step-by-step explanation:
I assume it is meant to draw 2 blue balls in a row out of the full pool of balls (no other draws happen before or during this process).
tricky, your teacher.
I think the temptation is to simply say 1/3×1/3 = 1/9.
but is it ?
the probabilty to draw one blue ball out of the complete system (no ball missing) is
x / (6+4+x) = 1/3
x = (6+4+x)/3
3x = 6 + 4 + x = 10 + x
2x = 10
x = 5
so, we have a system of 6 orange, 4 green and 5 blue balls (15 all together) .
the probability at our first pull to draw a blue ball is the indicated 5/15 = 1/3.
but now, for the second ball, we have only 6 orange, 4 green and 4 blue balls in the pool (14 altogether).
and so the probability to draw a blue ball out of this is
4/14 = 2/7.
therefore, the probability to draw 2 blue balls is now the combination
1/3 × 2/7 = 2/21
aha ! so, it is a little bit less than the originally suspected probability of 1/9.
500 students. if 200 students= 40% and you need to find the full 100% they you would add another 200 students or 40% and then you would add another 100 students or 20%. when you add all them up you get 40%+40%+20%= 100% and 200+200+100=500.
Given:
The price of shoes after discount = 27
Discount % = 40%
To find:
The original price of shoes before discount.
Solution:
Let x be the original price of shoes before discount.
The price of shoes after 40% discount is



The price of shoes after discount = 27



Therefore, the original price of the shoes is 45.
Answer:
1 / 18
Step-by-step explanation:
Odds = 1 : 17
Probability = odd * (17 ÷ sum of odd ratio)
Sum of odd ratio = ( 1 + 17) = 18
= (1 / 17) * (17 / 18)
= 1 / 18
Problem 1
With limits, you are looking to see what happens when x gets closer to some value. For example, as x gets closer to x = 2 (from the left and right side), then y is getting closer and closer to y = 1/2. Therefore the limiting value is 1/2
Another example: as x gets closer to x = 4 from the right hand side, the y value gets closer to y = 4. This y value is different if you approach x = 0 from the left side (y would approach y = 1/2)
Use examples like this and you'll get the results you see in "figure 1"
For any function values, you'll look for actual points on the graph. A point does not exist if there is an open circle. There is an open circle at x = 2 for instance, so that's why f(2) = UND. On the other hand, f(0) is defined and it is equal to 4 as the point (0,4) is on the function curve.
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Problem 2
This is basically an extension of problem 1. The same idea applies. See "figure 2" (in the attached images) for the answers.