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kvv77 [185]
3 years ago
13

A math test has 12 multiplication problems and 24 division problems.

Mathematics
2 answers:
gayaneshka [121]3 years ago
5 0
The answer 1/2. .......
OleMash [197]3 years ago
3 0

Answer:

the answer is 1/2

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Is the function f(x) =(4)^x -2 an exponential function. If so, identify the base. If not, why not?
Ne4ueva [31]

Answer:

Yes.

Base: 4

Step-by-step explanation:

Since we have 4 to the power of x, we do indeed have an exponent. The -2 just signifies vertical movement down.

7 0
3 years ago
A number to the 8th power divided by the same number to the 5th power equals 216
strojnjashka [21]

Answer:

X=6

Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
Round 9.77 to the nearest tenth
djyliett [7]
9.77 to the nearest tenths

first, find the number that is in the tenths place....it is 7....now look at the number directly to the right of it....if that number is 5 or greater, u would round that 7 up to an 8...but if that number is 4 or below, ur 7 would stay the same.
So the number directly to the right of 7 is 7...and since it is greater then 5, u have to round the 7 in the tenths place up to 8.

solution is : 9.8
3 0
3 years ago
Read 2 more answers
Can I get help with finding the Fourier cosine series of F(x) = x - x^2
trapecia [35]
Assuming you want the cosine series expansion over an arbitrary symmetric interval [-L,L], L\neq0, the cosine series is given by

f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx

You have

a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx
a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}
a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)
a_0=-\dfrac{2L^2}3

a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}

and so

a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}

So the cosine series for f(x) periodic over an interval [-L,L] is

f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx
4 0
3 years ago
When two lines have the same slope they are parallel. using this statement, decide whether the two lines below are parallel or n
bearhunter [10]

Answer:

They're not parallel, because 4x and 12x are not the same slope

4 0
3 years ago
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