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dangina [55]
3 years ago
14

Based on the NYC Department of Health Community Health Survey in 2010, a 95% confidence interval for the proportion of New Yorke

rs who were tested for HIV in the past 12 months is (29.9%, 32.9%). If the population size is 6 million in 2010, with 95% confidence, we know that at least how many New Yorkers were tested for HIV within the past 12 months?
Mathematics
1 answer:
g100num [7]3 years ago
8 0

Answer:

With 95% confidence, at least 1,794,000 were tested for HIV within the past 12 months

Step-by-step explanation:

The lower bound of the confidence interval is 29.9%.

So, with 95% confidence, we know that at least 29.9% of the New York population tested for HIV.

Out of 6 million, that is:

0.299*6000000 = 1,794,000

With 95% confidence, at least 1,794,000 were tested for HIV within the past 12 months

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3 years ago
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What is 32/1 divided by 1/6 i need help this is for my project DUE tomorrow please help!!!!
SCORPION-xisa [38]
32/1 divided by 1/6

Use "Keep, Change, Flip"
32/1 * 6/1

The answer is 192
3 0
3 years ago
The accounting department analyzes the variance of the weekly unit costs reported by two production departments. A sample of 16
dusya [7]

Answer:

F=\frac{s^2_2}{s^2_1}=\frac{5.5}{2.5}=2.2

Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have n_2 -1 =16-1=15 and for the denominator we have n_1 -1 =16-1=15 and the F statistic have 15 degrees of freedom for the numerator and 15 for the denominator. And the P value is given by:

p_v =2*P(F_{15,15}>2.2)=0.138

For this case the p value is highert than the significance level so we haev enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviations are not significantly different

Step-by-step explanation:

Information given

n_1 = 16 represent the sampe size 1

n_2 =16 represent the sample 2

s^2_1 = 2.5 represent the sample deviation for 1

s^2_2 = 5.5 represent the sample variance for 2

\alpha=0.10 represent the significance level provided

The statistic is given by:

F=\frac{s^2_2}{s^2_1}

Hypothesis to test

We want to test if the variations in terms of the variance are equal, so the system of hypothesis are:

H0: \sigma^2_1 = \sigma^2_2

H1: \sigma^2_1 \neq \sigma^2_2

The statistic is given by:

F=\frac{s^2_2}{s^2_1}=\frac{5.5}{2.5}=2.2

Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have n_2 -1 =16-1=15 and for the denominator we have n_1 -1 =16-1=15 and the F statistic have 15 degrees of freedom for the numerator and 15 for the denominator. And the P value is given by:

p_v =2*P(F_{15,15}>2.2)=0.138

For this case the p value is highert than the significance level so we haev enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviations are not significantly different

5 0
3 years ago
What is the surface area of the net below?<br> 4 cm<br> 7.2 cm<br> 12 cm
Ulleksa [173]

Answer: 163.2 cm^2

(4*7.2) + (7.2*12) + (12*4)

28.8 + 86.4 + 48

163.2

If that is the answer your looking for then brainliest pwease! <3

7 0
2 years ago
I need to explain/show work.<br> Help please
Fittoniya [83]

Answer:

adult tickets = 17, children tickets = 9

Step-by-step explanation:

Let x be the number of children and y the number of adults

Then given that 26 tickets are sold, we can write

x + y = 26 → (1)

Given that ticket cost was $194 we can write

5.5x + 8.5y = 194 → (2)

Rearrange (1) expressing y in terms of x by subtracting x from both sides

y = 26 - x → (3)

Substitute y = 26 - x into (2)

5.5x + 8.5(26 - x) = 194 ← distribute and simplify left side

5.5x + 221 - 8.5x = 194

- 3x + 221 = 194 ( subtract 221 from both sides )

- 3x = - 27 ( divide both sides by - 3 )

x = 9

Substitute x = 9 into (3) for corresponding value of y

y = 26 - 9 = 17

Hence number of adult tickets sold = 17

number of children tickets sold = 9

5 0
3 years ago
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