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DiKsa [7]
3 years ago
14

The value of 3^4+5•5=

Mathematics
1 answer:
balandron [24]3 years ago
5 0

Answer:

106

Step-by-step explanation:

3^4=81

5·5=25

81+25=106

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-7x - 2y = 19<br> 4x + y = -12<br> Solve the system
nalin [4]

-7x - 2y = 19

4x + y = -12

Set y equal to each other (opposite signs are fine and you could also set x equal instead of y)

-7x - 2y = 19

8x + 2y = -76

Add equations together

x = -52

Plug x value into an equation

4(-52) + y = -12

Solve for y

-208 + y = -12

y = 196

Hope this helps! ;)

4 0
3 years ago
HAIDIEIEBFIEIQPKDNFJRJRFFGFFE
AVprozaik [17]

Answer:

thats alot

Step-by-step explanation:

feels bad to be in that position, fallen soldier :P

4 0
3 years ago
Read 2 more answers
A company rents out 15 food booths and 23 game booths at the county fair. The fee for a food booth is $75 plus $9 per day. The f
Lapatulllka [165]

Answer:

M =  2620 + 16d

M = total money paid or earned

d = # of days

Step-by-step explanation:

15  food

23 game

Total Money  =  M = 15 * 75  + 9 d   +  23* 65  + 7d

M = 15 * 75  + 9 d   +  23* 65  + 7d

M  =  1125  + 1495 + 16d

M =  2620 + 16d

5 0
3 years ago
What is equal to the expression (4^-5)^3
Leona [35]

The answer is 1/1073741824 or about 9.313 * 10^-10

8 0
3 years ago
Read 2 more answers
13.......................
Alla [95]

Answer:

The answer is (d) ⇒ pq^{2}r\sqrt[3]{pr^{2}}

Step-by-step explanation:

* To simplify the cube roots:

 If its number then the number must be written in the form x³

 then we divide the power by 3 to cancel the radical

 If its variable we divide its power by 3 to cancel the radical

∵ \sqrt[3]{p^{4}q^{6}r^{5}}=p^{\frac{4}{3}}q^{\frac{6}{3}}r^{\frac{5}{3}}}

∴ p^{\frac{4}{3}}q^{2}}r^{\frac{5}{3}}=p^{1\frac{1}{3}}q^{2}r^{1\frac{2}{3}}

∵ p^{\frac{1}{3}}=\sqrt[3]{p}

∵ r^{\frac{2}{3}}=\sqrt[3]{r^{2}}

∴ p(p)^{\frac{1}{3}}q^{2}r(r)^{\frac{2}{3}}=p(\sqrt[3]{p})q^{2}r(\sqrt[3]{r^{2}})

∴ prq^{2}\sqrt[3]{pr^{2}}}

∴ The answer is (d)

5 0
3 years ago
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