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vovangra [49]
3 years ago
12

In a box there are two prizes that are worth $4, a single prize worth $20, and a single prize worth $200. A player will reach in

to the box and draw one of the prizes at random. What is the fair price for this game? Round your answer to the nearest hundredth, and do not include a $ sign or the word "dollars" in your response.
Mathematics
1 answer:
Ronch [10]3 years ago
6 0

Answer:

57

Step-by-step explanation:

The player has a 1/4 chance of drawing any of the 4 prizes. This means that the probability of drawing a prize of $4 is 1/2 because there are 2 prizes worth of $4. The probability of drawing a prize of $20 is 1/4 and the probability of drawing a prize of $200 is also 1/4. To find the fair price of the game, we have to calculate the expected value that the player will gain. This can be obtained by multiplying any possible value of a price for the probability of drawing a prize of that value and adding all the obtained values togueter. Thus, the fair price of the game is

4 * \frac{1}{2} + 20 * \frac{1}{4} + 200 * \frac{1}{4} = 57

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Ilia_Sergeevich [38]

so together the amount of people who chose beef should be 4/12 since you must find the greatest commen factor. Then you should add 4/12 and  24 im thinking and you would get 24.3333 but if your looking for a mix number it would be 24 3333/1000

hope this helps!


7 0
4 years ago
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N76 [4]

Answer:

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Step-by-step explanation:


3 0
3 years ago
Evaluate n+2x2 when n=3 and x=−2.
krok68 [10]

Answer:

When n=3 and x=−2  the answer is 11.

Step-by-step explanation:

Given:

Let p (n,x) be the function such that

p (n,x) = n + 2x^{2}

To Find:

p (n,x) = p ( 3, -2) = ?

Solution:

p (n,x) = n + 2x^{2}

Substituting n = 3 and x = -2 we get

p (3, -2) = 3 + 2(-2)^{2}

Negative square gives positive number therefore (-2)²=4

p (3, -2) = 3 + 2\times 4

p (3, -2) = 3 + 8\\p (3, -2) = 11

When n=3 and x=−2  the answer is 11.

7 0
3 years ago
In the rectangle ABCD the angle OAV is 48degrees smaller than the angle AOB .Find the angles of the triangle AOB
mart [117]
Im giving you instrutions to get the answer its simple:D
The figure above shows a circular sector OAB<span> , subtending an </span>angle<span> of θ radians ... The points A and B lie on the circle so that the </span>angle AOB<span> is 1.8 radians. .... c) </span>Calculate<span> the smallest </span>angle<span> of the </span>triangle<span>ABC , giving the answer in </span>degrees<span>, .... Given that the length of the arc AB is </span>48<span> cm , </span>find<span> the area of the shaded region</span><span>.
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3 0
3 years ago
I need help trying to figure this out I think I have and answer but I want to make sure.
yKpoI14uk [10]

Answer:

34

Step-by-step explanation:

The mean is calculated as

mean = \frac{frequency(midpoint)}{frequency}

let x be the missing frequency, then

Total frequency × midpoint

= (16 × 2) + 7x + (20 × 12) + (10 × 17) = 32 + 7x + 240 + 170 = 442 + 7x

Total frequency = 16 + x + 20 + 10 = 46 + x, thus

\frac{242+7x}{46+x} = 8.5 ( cross- multiply )

442 + 7x = 8.5(46 + x)

442 + 7x = 391 + 8.5x ( subtract 8.5x from both sides )

442 - 1.5x = 391 ( subtract 442 from both sides )

- 1.5x = - 51 ( divide both sides by - 1.5 )

x = 34

The missing frequency is 34

3 0
3 years ago
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