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Lynna [10]
3 years ago
5

Help me with my homework

Mathematics
2 answers:
soldi70 [24.7K]3 years ago
4 0

Answer: A. There are three terms

Concept:

In an algebraic expression, there are several specific terms:

  • Constant: the individual number that has no variable with it, or in east word, it is isolated.
  • Variable: any unknown value, which is usually presented by alphabets.
  • Coefficients: the numbers that are bounded with a variable, usually in front of a variable.
  • Terms: the number of individuals present in the expression, which is constants and [variable + coefficients].
  • Like terms: terms that have the same variables and powers.

If you are still confused, you may refer to the attachment below for a graphical explanation.

Solve:

<u>a. There are three terms.</u> \boxed{FALSE}

- 14b

- -7

- 8b

- b

There are in total four individuals, which means there are four terms.

<u>b. There is one constant term.</u> \boxed{TRUE}

- 14b is a [variable + coefficient]

- -7 is a [constant]

- 8b is a [variable + coefficient]

- b is a [variable]

Therefore, there is one constant term.

<u>c. The coefficients are 14, 8, and 1</u> \boxed{TRUE}

- 14b →→→ 14 is the [coefficient]

- -7 →→→ is a [constant]

- 8b →→→ 8 is the [coefficient]

- b →→→ 1 is the [coefficient]

Therefore, 14, 8, and 1 are coefficients.

<u>d. Three of the terms are like terms</u> \boxed{TRUE}

- 14b →→→ b is the [variable]

- -7 →→→ is a [constant]

- 8b →→→ b is the [variable]

- b →→→ b is the [variable]

Since 14b, 8b, and b share the common variable, there are three like terms.

Hope this helps!! :)

Please let me know if you have any questions

EleoNora [17]3 years ago
3 0

Answer:

a because I dont know why but some one told me it was this

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Evaluate to one decimal place
ANTONII [103]

Answer:

<u>The correct answer is C. 1.6</u>

Step-by-step explanation:

Let's recall that e or Euler's number is a mathematical constant that is the base of the natural logarithm, in other words, the unique number whose natural logarithm is equal to one. The value of e is approximately 2.71828.

Now, replacing e, we have:

2.71828∧(1/2) = √2.71828 = 1.6 (Rounding to one decimal place)

<u>The correct answer is C. 1.6</u>

3 0
3 years ago
Suppose a simple random sample of size nequals81 is obtained from a population with mu equals 79 and sigma equals 18. ​(a) Descr
Daniel [21]

Answer:

(a) The sampling distribution of\overline{X} = Population mean = 79

(b)  P ( \overline{X} greater than 81.2 ) =  0.1357

(c) P (\overline{X} less than or equals 74.4 ) = .0107

(d) P (77.6 less than \overline{X} less than 83.2 ) = .7401

Step-by-step explanation:

Given -

Sample size ( n ) = 81

Population mean (\nu) = 79

Standard deviation (\sigma ) = 18

​(a) Describe the sampling distribution of \overline{X}

For large sample using central limit theorem

the sampling distribution of\overline{X} = Population mean = 79

​(b) What is Upper P ( \overline{X} greater than 81.2 )​ =

P(\overline{X}> 81.2)  = P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}> \frac{81.2 - 79}{\frac{18}{\sqrt{81}}})

                    =  P(Z> 1.1)

                    = 1 - P(Z<   1.1)

                    = 1 - .8643 =

                    = 0.1357

(c) What is Upper P (\overline{X} less than or equals 74.4 ) =

P(\overline{X}\leq  74.4) = P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq  \frac{74.4- 79}{\frac{18}{\sqrt{81}}})

                    = P(Z\leq  -2.3)

                    = .0107

​(d) What is Upper P (77.6 less than \overline{X} less than 83.2 ) =

P(77.6< \overline{X}<   83.2) = P(\frac{77.6- 79}{\frac{18}{\sqrt{81}}})< P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq  \frac{83.2- 79}{\frac{18}{\sqrt{81}}})

                                = P(- 0.7< Z<   2.1)

                                 = (Z<   2.1) - (Z<   -0.7)

                                  = 0.9821 - .2420

                                   = 0.7401

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3 years ago
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Answer:

-8 and 1

Step-by-step explanation:

-8 × 1 = -8

-8 + 1 = -7

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Answer:

-36+7x

Step-by-step explanation:

8 0
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