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sergejj [24]
3 years ago
15

Identify the self assessment test that each

Mathematics
1 answer:
ladessa [460]3 years ago
5 0

there is not enough info for this

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Please help me I need it please help I'm begging you
Citrus2011 [14]

Answer:

5

Step-by-step explanation:

def is similar to abc so the 7.5 side is 1.5x bigger so divide 7.5 by 3 and multiply by 2

6 0
2 years ago
It took Peter 3 hours to drive to his friend in Connecticut when he was driving with the average speed 54 mph. How much time wil
pishuonlain [190]

Answer: 2.7 hours

Step-by-step explanation:

3 x 54 = 162, 162 is how many miles the drive is. If he is going 60 mph you have to divide 162/60 and you get 2.7 hours

4 0
3 years ago
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(Based on Q1 ~ Q3) According to the Bureau of the Census, 18.1% of the U.S. population lives in the Northeast, 21.9% inn the Mid
vekshin1

Answer:

We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.

Step-by-step explanation:

The null Hypothesis: Geographical distribution of hotline callers could be the same as the U.S. population distribution

Alternative hypothesis: Geographical distribution of hotline callers could not be the same as the U.S. population distribution

The populations considered are the Midwest, South, Northeast, and west.

The number of categories, k = 4

Number of recent calls = 200

Let the number of estimated parameters that must be estimated, m = 0

The degree of freedom is given by the formula:

df = k - 1-m

df = 4 -1 - 0 = 3

Let the significance level be, α = 5% = 0.05

For  α = 0.05, and df = 3,

from the chi square distribution table, the critical value = 7.815

<u>Observed and expected frequencies of calls for each of the region:</u>

<u>Northeast</u>

Observed frequency = 39

It contains 18.1% of the US Population

The probability = 0.181

Expected frequency of call = 0.181 * 200 = 36.2

<u>Midwest</u>

Observed frequency = 55

It contains 21.9% of the US Population

The probability = 0.219

Expected frequency of call = 0.219 * 200 =43.8

<u>South</u>

Observed frequency = 60

It contains 36.7% of the US Population

The probability = 0.367

Expected frequency of call = 0.367 * 200 = 73.4

<u>West</u>

Observed frequency = 46

It contains 23.3% of the US Population

The probability = 0.233

Expected frequency of call = 0.233 * 200 = 46

x^{2} = \sum \frac{(O_{i} - E_{i})  ^{2} }{E_{i} } ,   i = 1, 2,.........k

Where O_{i} = observed frequency

E_{i} = Expected frequency

Calculate the test statistic value, x²

x^{2} = \frac{(39 - 36.2)^{2} }{36.2} + \frac{(55 - 43.8)^{2} }{43.8} + \frac{(60 - 73.4)^{2} }{73.4} + \frac{(46 - 46.6)^{2} }{46.6}

x^{2} = 5.535

Since the test statistic value, x²= 5.535 is less than the critical value = 7.815, the null hypothesis will not be rejected, i.e. it will be accepted. We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.  

7 0
3 years ago
Which function is not defined at 0? Please help urgent
Vlada [557]

Answer:

b and g

Step-by-step explanation:

a. is y = 0³ = 0

b. is y = ln(0), which is undefined because ln(x) is only defined for x > 0

c. is y = 1 / (1 + e^-0) = 1 / (1 + 1) = 1/2

d. is y = 0

e. is y = 0² = 0

f. is y = sin(0) = 0

g. is y = 1/0, which is undefined because division by 0 is undefined

h. is y = e^0 = 1

i. is y = |0| = 0

j. is y = √0 = 0

7 0
3 years ago
What's the expanded form of 32.043
jok3333 [9.3K]
<span>32.043=30+2+0.04+0.003</span>
7 0
3 years ago
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