Answer:
The correct option is (c) 13.277.
Step-by-step explanation:
The observed data is:
Location Observed sales (units)
Northside 70
Pleasant Township 75
Southwick 70
I-90 50
Venice Avenue 35
TOTAL 300
The test statistic for the Goodness of fit test is:
For <em>k</em> independent samples this test statistic follows a Chi-square distribution with degrees of freedom (<em>k</em> - 1).
The sample size in this case is, <em>k</em> = 5.
The degrees of freedom is, (<em>k</em> - 1) = 4.
The level of significance is, <em>α</em> = 0.01.
The critical value of the test is:
**Use the Chi-square table.
Thus, the critical value is 13.277.
<span>2x+3y=3
</span><span>-3x-2y=8
3y=3-2x
-2y = 8+3x
y = 1 - 2x/3
y = -4 - 3x/2
</span>1 - 2x/3 = -4 - 3x/2
5 = - 3x/2 + 2x/3
5 = -9x/6 + 4x/6
5 = -5x/6
x = 5 * 6/-5
x = -6
No plug it in.
<span>2x+3y=3 ; x = -6
-12 + 3y = 3
3y=3+12
3y=15
y = 5
So </span>x = -6 and y = 5
Next multiples of the unit fraction 1/5 are
2/5
3/5
4/5
5/5 = 1
Hope this helps.. :)
The equation relating length to width
L = 3W
The inequality stating the boundaries of the perimeter
LW <= 112
When you plug in what L equals in the first equation into the second equation, you get
3W * W <= 112
evaluate
3W^2 <= 112
3W <=
W <=
cm