Answer:
Step-by-step explanation:
<u>Given:</u>
- Initial mass is m = 80 g.
- Half life = 10 days
- Total time = 60 days
<u>Number of half-life periods:</u>
<u>Equation for remaining sample:</u>
- s = m*(1/2)^r
- s = 80*(1/2)^6 = 80/64 = 1.25 g
Use the trig identity
2*sin(A)*cos(A) = sin(2*A)
to get
sin(A)*cos(A) = (1/2)*sin(2*A)
So to find the max of sin(A)*cos(A), we can find the max of (1/2)*sin(2*A)
It turns out that sin(x) maxes out at 1 where x can be any expression you want. In this case, x = 2*A.
So (1/2)*sin(2*A) maxes out at (1/2)*1 = 1/2 = 0.5
The greatest value of sin(A)*cos(A) is 1/2 = 0.5
Step-by-step explanation:
2w+3(2w)=30
8w=30
w=3.75
l=11.25
Answer:
(12)3=36
Step-by-step explanation:
i don't know.. I think this is what the question is trying to say XD
