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3 years ago

Functions of the form y = abx, where b > 0 and b ≠ 0, are called ____ functions.

Mathematics

1 answer:

guapka [62]3 years ago

7 0

Answer:

Exponential function.

Step-by-step explanation:

We are given that a function of the form

$y=ab^x$

Where $b\neq 0$ and b>0

Exponential function: The function is of the form

$y=b^x$

Where b is a positive constant and greater than 0 and x is any real number.

The given function satisfied the define of exponential function.

Hence, the function of the form $y=ab^x$

Where b>0 and $b\neq 0$ are called exponential function.

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How do you solve this step by step

nydimaria [60]

Work shown above! x = 7
To solve use the supplementary angle next to the unknown angle to find an expression for that unknown angle and use that with the expressions inside the triangle to set equal to 180 and solve for x.

hope this helps c:

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2 years ago

For the figure above: Assume that <ABD has a mesure of 105° ANSWER ASAP WILL GIVE 15 POINTS AND BRAINLIEST

kykrilka [37]

Answer:

DBC = 75

Step-by-step explanation:

ABD and DBC are supplementary angles. They add to 180 degrees.

ABD + DBC = 180

105 + DBC = 180

Subtract 105 from each side

105-105 + DBC = 180-105

DBC = 75

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2 years ago

Read 2 more answers

Can I get help with finding the Fourier cosine series of F(x) = x - x^2

trapecia [35]

Assuming you want the cosine series expansion over an arbitrary symmetric interval $[-L,L]$ , $L\neq0$ , the cosine series is given by

$f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx$

You have

$a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx$
$a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}$
$a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)$
$a_0=-\dfrac{2L^2}3$

$a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx$

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

$\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}$

and so

$a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}$

So the cosine series for $f(x)$ periodic over an interval $[-L,L]$ is

$f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx$

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3 years ago

Describe an animal adaptation and explain how it helps survival.

marin [14]

Answer and Step-by-step explanation:

Animal adaption for Birds.

Birds who live on a tropical island with large, hard shell nuts.

The birds have small beaks, but over time, their beaks become bigger, stronger, and sharper, so that it can break into the hard shell nuts, allowing them to eat the nuts.

#teamtrees #WAP (Water And Plant)

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2 years ago

Consider the diagram. What is the length of segment AB?

Vlad [161]

The answer would be B

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