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NARA [144]
3 years ago
6

Solve for x in the equation x-4=7

Mathematics
2 answers:
Lera25 [3.4K]3 years ago
7 0
What you do first is add 4 to both sides of the equation to get x alone and you get x=11. X is equal to 11.
TEA [102]3 years ago
6 0

Answer:

x=11

Step-by-step explanation:

we have

x-4=7

Solve for x

Adds 4 both sides

x-4+4=7+4

x=11

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A circle's diameter is 4 feet.
Soloha48 [4]

Answer:

13

Step-by-step explanation:

The formula for cirmference is

C= π2 * r

we're using 3.14 as pi and r = radius.

the radius is always half of the diameter.

So in this case since the diamter is 4, the radius is 2. let's substitute these numbers.

C= 3.14 *2*2 and there your answer is 12.56 which rounded to the nearest tenth is 13.

Hope this helps :)

6 0
2 years ago
You are saving $5 each week to attend a summer program that costs $300. You already have $84. You have also received a $50 schol
rosijanka [135]
D.34 more weeks left of saving because you have $166 more dollars to go after your $50 dollar scholarship program and the 16 weeks of saving $84 dollars.
6 0
3 years ago
what is the radius of a circle with a circumference of 125 cm? round your answer to the nearest whole number .use 3.14
Lerok [7]

Answer:

19.9 i think

Step-by-step explanation:

125/3.14=39.8

39.8/2=19.9

hope i helped

5 0
4 years ago
Read 2 more answers
the eccentricity of a hyperbola is defined as e=c/a. find an equation with vertices (1,-3) and (-3,-3) and e=5/2
Ksivusya [100]

Answer:

\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1.

Step-by-step explanation:

If (α, β) are the coordinates of the center of the hyperbola, then its equation of the hyperbola is \frac{(x - \alpha )^{2} }{a^{2} } - \frac{(y - \beta )^{2} }{b^{2} } = 1.

Now, the vertices of the hyperbola are given by (α ± a, β) ≡ (1,-3) and (-3,-3)

Hence, β = - 3 and α + a = 1 and α - a = -3

Now, solving those two equations of α and a we get,  

2α = - 2, ⇒ α = -1 and

a = 1 - α = 2.

Now, eccentricity of the hyperbola is given by b^{2} = a^{2}(e^{2}  - 1) = 4[(\frac{5}{2} )^{2} -1] = 21 {Since e = \frac{5}{2} given}

Therefore, the equation of the given hyperbola will be  

\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1. (Answer)

6 0
3 years ago
Find parametric equations for the sphere centered at the origin and with radius 3. Use the parameters s and t in your answer.
sdas [7]
Radius, r = 3

The equation of a sphere entered at the origin in cartesian coordinates is

x^2 + y^2 + z^2 = r^2 

That in spherical coordinates is:

x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)

where you can make u = r cos(phi) to obtain the parametrical equations

x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u

where theta goes from 0 to 2π and u goes from -r to r.

In our case r = 3, so the parametrical equations are:

Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u
6 0
3 years ago
Read 2 more answers
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