3 years ago

Help please it's a math assignment

Mathematics

1 answer:

expeople1 [14]3 years ago

3 0

I'm pretty sure it's graph A. I apologize if it's wrong hope this helped.

You might be interested in

500(x - 3) = 5000<br><br><br><br> x = _____

olya-2409 [2.1K]

Answer:

Step-by-step explanation:

500(x - 3) =5000

x - 3 = 5000/500

x - 3 = 10

x = 10 + 3

x = 13

6 0

2 years ago

The sum of 20.7 and a number is 50.5. Which equation could you use to solve the problem? What should you do to each side of the

Arlecino [84]

Answer:

Equation to solve this: 50.5-20.7=a number

Answer: 29.8

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

I theater sells tickets for a concert. Tickets for lower-level seats sell for $35 each and tickets for upper-level seats sell fo

lora16 [44]

Let X= the number of tickets sold at $35 each

Let 350 -X = the number of tickets sold at $25 each

The number of tickets sold for each type will be computed as follows:

X(35)+(350-X)25=10250

35X+8750-25X=10250

10X=10250-8750

X=1500/10

X=150 the number of tickets sold at $35 each

350-150 the number of tickets sold at $25 each

To recheck:

150(35)+200(25)

5250+5000

10250

7 0

2 years ago

What are the potential solutions to the equation 2ln(x+3)=0

skad [1K]

$2\ln(x+3)=0\implies \ln(x+3)^2=0\implies e^{\ln(x+3)^2}=e^0\implies (x+3)^2=1$

Expanding the left side gives

$x^2+6x+9=1\implies x^2+6x+8=0\implies (x+4)(x+2)=0$

which gives two solutions, $x=-4$ and $x=-2$ . But if $x=-4$ , then $\ln(x+3)=\ln(-1)$ , but this number isn't real, so $x=-4$ is an extraneous solution. Meanwhile if $x=-2$ , you get $\ln(-2+3)=\ln1=0$ , so this solution is correct.

"Potential solutions" might refer to both possibilities, but there is only one actual (real) solution.

4 0

3 years ago

Read 2 more answers

Need help with this question

miskamm [114]

Y = t + 9. hope this helps

8 0

2 years ago