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marissa [1.9K]
3 years ago
14

Word problem on direct variation

Mathematics
1 answer:
Ludmilka [50]3 years ago
7 0

Answer:

acceleration would be 9 meters per second squared

Step-by-step explanation:

If quantity "A" varies directly with quantity "B", then we can write:

A = kB

Now, this problem says that force (f) varies directly with acceleration (a). So we can write:

f = ka

Given f = 100 and a = 10, so we substitute and find k (the proportionality constant). Shown below:

f = ka

100 = k(10)

k = 100/10

k = 10

So, we have

f = 10a

Now, force is 90, so what's the acceleration?

90 = 10a

a = 90/10

a = 9

So, the acceleration would be 9 meters per second squared

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If f(x) = 2 - x^1/2 and g(x) = x^2 – 9, what is the domain of g(x) divided f(x)?
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~Shoto Todoroki here~

Let's consider what we are asked. The domain is defined as a set of points that satisfy the equation on the x-ordinate.

So, essentially, we need to find if and what the restriction on x is.

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