It is 25-6 7 :) that gonna be right
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
<span>Equation at the end of step 2 :</span> 6x2 - x - 4 = 0 <span>((2•3x2) - x) - 4 = 0
</span><span>Step 2 :</span>Trying to factor by splitting the middle term
<span> 2.1 </span> Factoring <span> 6x2-x-4</span>
The first term is, <span> <span>6x2</span> </span> its coefficient is <span> 6 </span>.
The middle term is, <span> -x </span> its coefficient is <span> -1 </span>.
The last term, "the constant", is <span> -4 </span>
Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 6</span> • -4 = -24</span>
Step-2 : Find two factors of -24 whose sum equals the coefficient of the middle term, which is <span> -1 </span>.
<span><span> -24 + 1 = -23</span><span> -12 + 2 = -10</span><span> -8 + 3 = -5</span><span> -6 + 4 = -2</span><span> -4 + 6 = 2</span><span> -3 + 8 = 5</span><span> -2 + 12 = 10</span><span> -1 + 24 = 23
</span></span>
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
<span>Equation at the end of step 2 :</span><span> 6x2 - x - 4 = 0 </span>
Answer:
The correct option is D. 2/7
Step-by-step explanation:
Consider the provided information.
There are 8 volunteers including Andrew and Karen, 4 people are to be selected at random to organize a charity event.
We need to determine the probability Andrew will be among the 4 volunteers selected and Karen will not.
We want to select Andrew and 3 others but not Karen in the group.
Thus, the number of ways to select 3 member out of 8-2=6
(We subtract 2 from 8 because Andrew is already selected and we don't want Karen to be selected, so subtract 2 from 8.)
The required probability is:

Hence, the correct option is D. 2/7
Answer:
Step-by-step explanation:
16^3 - 8^3
Take out 8^3 as a common factor.
16^3 = 2^3 * 8^3
8^3(2^3 - 1)
8^3(8 - 1) = 8^3 * 7
(4^3 + 2^3) Expand
64 + 8 Combine
72
72 = 9 * 8
Conclusion
(8*3 * 7 )(9*8)
7*9 = 63
So any number containing 63 will divide into the reduced form of
(16^3–8^3)(4^3 +2^3)