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arlik [135]
4 years ago
10

A^2 b^2 c^2 for a =2, b and c=4

Mathematics
1 answer:
-Dominant- [34]4 years ago
6 0

Answer:

1,024

Step-by-step explanation:

2*2*4*4*4*4=1024

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Tomtit [17]
It is 25-6 7 :) that gonna be right
3 0
3 years ago
What is the value of x? 6x−2(x 4)=12
jonny [76]

Observation : No two such factors can be found !! 
Conclusion : Trinomial can not be factored

<span>Equation at the end of step  2  :</span>  6x2 - x - 4 = 0 <span>((2•3x2) - x) - 4 = 0 </span><span>Step  2  :</span>Trying to factor by splitting the middle term

<span> 2.1 </span>    Factoring <span> 6x2-x-4</span> 

The first term is, <span> <span>6x2</span> </span> its coefficient is <span> 6 </span>.
The middle term is, <span> -x </span> its coefficient is <span> -1 </span>.
The last term, "the constant", is <span> -4 </span>

Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 6</span> • -4 = -24</span> 

Step-2 : Find two factors of  -24  whose sum equals the coefficient of the middle term, which is  <span> -1 </span>.

<span><span>     -24   +   1   =   -23</span><span>     -12   +   2   =   -10</span><span>     -8   +   3   =   -5</span><span>     -6   +   4   =   -2</span><span>     -4   +   6   =   2</span><span>     -3   +   8   =   5</span><span>     -2   +   12   =   10</span><span>     -1   +   24   =   23
</span></span>

Observation : No two such factors can be found !! 
Conclusion : Trinomial can not be factored

<span>Equation at the end of step  2  :</span><span> 6x2 - x - 4 = 0 </span>

3 0
3 years ago
From a group of 8 volunteers, including Andrew and Karen, 4 people are to be selected at random to organize a charity event. Wha
Helga [31]

Answer:

The correct option is D. 2/7

Step-by-step explanation:

Consider the provided information.

There are 8 volunteers including Andrew and Karen, 4 people are to be selected at random to organize a charity event.

We need to determine the probability Andrew will be among the 4 volunteers selected and Karen will not.

We want to select Andrew and 3 others but not Karen in the group.

Thus, the number of ways to select 3 member out of 8-2=6

(We subtract 2 from 8 because Andrew is already selected and we don't want Karen to be selected, so subtract 2 from 8.)

The required probability is:

\dfrac{^6C_3}{^8C_4}=\dfrac{\frac{6!}{3!3!}}{\frac{8!}{4!4!}}\\\\\\\dfrac{^6C_3}{^8C_4}=\frac{20}{70}\\\\\\\dfrac{^6C_3}{^8C_4}=\dfrac{2}{7}

Hence, the correct option is D. 2/7

6 0
4 years ago
Prove that the value of the expression<br> (16^3–8^3)(4^3 +2^3) is divisible by 63.
Darya [45]

Answer:

Step-by-step explanation:

16^3 - 8^3

Take out 8^3 as a common factor.

16^3 = 2^3 * 8^3

8^3(2^3 - 1)  

8^3(8 - 1) = 8^3 * 7

(4^3 + 2^3)     Expand

64 + 8            Combine

72

72 = 9 * 8

Conclusion

(8*3 * 7 )(9*8)

7*9 = 63

So any number containing 63 will divide into the reduced form of

(16^3–8^3)(4^3 +2^3)

7 0
2 years ago
The cost of a taxi ride is $5 plus $0.50 per mile write an algebraic expression that models the cost of a taxi of M miles. A-m(5
Alex787 [66]
The answer would be A or D
3 0
3 years ago
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