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arlik [135]
3 years ago
10

A^2 b^2 c^2 for a =2, b and c=4

Mathematics
1 answer:
-Dominant- [34]3 years ago
6 0

Answer:

1,024

Step-by-step explanation:

2*2*4*4*4*4=1024

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Find the perimeter of the quadrilateral.
levacccp [35]

<em><u>Question:</u></em>

Find the perimeter of the quadrilateral. if x = 2 the perimeter is ___ inched.

The complete figure of this question is attached below

<em><u>Answer:</u></em>

<h3>The perimeter of the quadrilateral is 129 inches</h3>

<em><u>Solution:</u></em>

The complete figure of this question is attached below

Given that, a quadrilateral with,

Side lengths are:

4x^2 + 8x\ inches \\\\3x^2-5x+20\ inches \\\\7x + 30\ inches \\\\31\ inches

The values of the side lengths when x = 2 are

(4x^2+8x)=(4\times 2^2+8\times 2)=(4\times 4+16)=16+16=32\ inch\\\\(3x^2-5x+20)=(3\times 2^2-5\times 2+20)=(3\times 4-10+20)=12+10=22\ inch\\\\(7x+30)=(7\times 2+30)=14+30=44\ inch

Perimeter of a quadrilateral = Sum of its sides

Perimeter of given quadrilateral = 32 + 22 + 44 + 31 = 129 inches

Thus perimeter of the quadrilateral is 129 inches

5 0
3 years ago
How many 1/4 pound hamburgers can you make from 3 1/2 pound of ground beef ​
Anna71 [15]

Answer:

14

Step-by-step explanation:

Divide 3 1/2 into 1/4

5 0
3 years ago
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Housing prices in a certain neighborhood average at $90.05 per square foot. If one house in this neighborhood is 1055 square fee
Gwar [14]
$90.05•1055=95,002.75

so the answer would be B. 95,000
3 0
3 years ago
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A rectangle has length that is 5 less than 2 times the width. Write an expression for the area of the rectangle.
a_sh-v [17]

We are given a relationship between the sides of a rectangle, that is, the length of one of its sides is 5 less two times its width, and we are asked to find an expression for the area. Let's remember that the area of a rectangle is equal to the product of the length of its side by its width. Let "w" be the length of the rectangle and "L" its lenght, then the area is given by the following formula:

A=Lw

We can use the relationship given in the problem, that is, its length being five less two times its width, that is:

L=5-2w

Replacing in the formula for the area we get:

A=(5-2w)w

Now we use the distributive law:

A=5w-2w^2

7 0
1 year ago
Helppppppppppppp plssssssssssss
beks73 [17]

area is found by multiplying length by width

so

26.4 times 12.25 =  

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