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3 years ago

A^2 b^2 c^2 for a =2, b and c=4

Mathematics

1 answer:

-Dominant- [34]3 years ago

6 0

Answer:

1,024

Step-by-step explanation:

2*2*4*4*4*4=1024

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Leslie and Daniel plan to put an above-ground pool in the backyard of their new home. The backyard is rectangular, 30 feet by 50

Brut [27]

1047.84ft² is not covered by the pool.
Find the area of the yard covered by pull using the area of a circle formula (the height is irrelevant in this case). If the diameter of the pool is 24 feet, its radius is 12 (half of the diameter)

A = 3.14r^2
A =3.14(144)
A = 452.16 ft²

Subtract the area of the pool from the area of the yard to get the area of the yard that is not covered by the pool. If the dimensions of the yard are 30ft by 50ft, you multiply them to get the area: 1500ft²

Total yard area: 1,500ft²
Area of yard without pool: 1,500ft² - 452.16ft² = 1047.84ft²

4 0

3 years ago

Do anyone know the answer to this? Answers please?

Amanda [17]

Answer:

Yes

Step-by-step explanation:

You can check whether the ratios form a proportion, by setting one piece of the ratios as x

Thus, we can use the equation 4/3.2=22/x.

From this, we get 4x=70.4.

Solving for x gives us 17.6.

5 0

2 years ago

Rewrite using a single positive exponent. 78 73

vivado [14]

Hey! I don’t know if this is what you mean.. but I tried to understand it.

78^1
73^1

Have a good day :)

3 0

2 years ago

A weed control company claims that each application of its product eliminates 1/2 of weeds. The number of weeds is modeled by f(

sp2606 [1]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

A family wants to build a rectangular garden on one side of a barn. If 600 feet of fencing is available to use, then what is the

vovangra [49]

Answer: (A) $A=300l-l^{2}$

(B) Length varies between 1 and 150

Step-by-step explanation: Suppose length is l and width is w.

The rectangular garden has perimeter of 600ft, which is mathematically represented as

$2l+2w=600$

Area of a rectangle is calculated as

$A=lw$

Now, we have a system of equations:

$2l+2w=600$

$A=lw$

Isolate w, so we have l:

$2w=600-2l$

w = 300 - l

Substitute in the area equation:

A = l(300 - l)

A = 300l - l²

(A) Function of area in terms of length is given by A = 300l - l²

(B) The practical domain for this function is values between 1 and 150.

(C) For the largest area, we need to determine the largest garden possible. For that, we take first derivative of the function:

A' = 300 - 2l

Find the values of l when A'=0:

300 - 2l = 0

2l = 300

l = 150

Replace l in the equation:

w = 300 - 150

w = 150

Now, calculate the largest area:

A = 150*150

A = 22500

The largest area the fence can enclose is 22500ft².

4 0

2 years ago