In physics, work is equal to the product of force and distance, given that the direction of force is the same with the direction of the distance.
W = Fd
The total force is
F = 1,700 N + 500 N = 2,200 N
Now, if the question is the work needed to lift the barbell from the ground, the distance would be 2 m. Hence, the work would be
W = (2,220 N)(2 m) = 4,400 N·m or 4,400 J
<span>The triangle on paper is 5 inches wide by 7 inches high.</span><span>
</span><span>
If 1 inch on paper is equal to 1.5 feet on paper, then you need to multiply all dimensions by 18 because 1.5 feet is equal to 18 inches and you are getting 18 inches on the real banner for every inch on the paper banner. </span><span>
5 * 18 = 90 inches from the base of the rear triangle.</span><span>
7 * 18 = 125 inches for the height of the rear triangle. </span><span>
</span><span>The area of the paper triangle will be 5 * 7 / 2 = 35/2 square inches.</span><span>
The area of the rear triangle will be 90 * 125 / 2 = 5625 square inches. </span><span>
regarding feet:
The base of the real banner will be 125/12 = 10.41666666....... feet.</span><span>
the height of the real banner will be 90 / 12 = 7.5 feet.</span><span>
the area of the real banner will be 5625 / 12^1 = 5625 / 144 = 39.0625 square feet.</span><span>
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Answer:

Step-by-step explanation:
-0.4(3i + 4i) - 0.3(-2i + 5j) + 0.2(-
+
j)
-1.2i - 1.6j + 0.6i - 1.5j -
i + 0.5j
Converting to fraction form;

<u>Solving the i part;</u>
= 
<u>Solving the j part;</u>
j
So -0.4a - o.3b + 0.2d =
- 