L-s=16
4s-5=l
4s-l=5
3s=21
s=7
l-7=16
l=16+7
l=23
The smaller number is 7 and the greater number is 23
Answer:
67
Step-by-step explanation:
7x9=63
63+4=67
The required Comparison of the inequalities are
- The |x – 1| + 1 > 15 represents the value of x lies between 13<x<15.
The range of values encompassing the region's junction is (-13, 15).
- If x is more than or equal to 15, then x-11+1>15 indicates the value of x is greater than or equal to 13. None of the regions in the intersection are empty.
<h3>What is inequality?</h3>
When comparing two numbers, an inequality indicates whether one is less than, larger than, or not equal to the other.
We take into account the various variables of the inequality
|x – 1| + 1 > 15
Therefore
|-x-1|+1-1<15-1
|-x-1|-1 <14
13<x<15
The required region lies between the inequality -13 <x< 15.
Simplify the inequality Ix-11+1 > 15 we get,
|x-1|+1 > 15
|x+1| +1-1 >15-1
|x-1| > 14
x> 15
x<-13
- If x has a value between -13 and x + 15, then the expression "|x-1|+1+115" is true. The range "(-13, 15)" contains the intersection of the region.
- If "|x-1|+1>15" then either "x >15" or "x-13" applies to the value of x. This region's intersection is unoccupied.
Read more about inequalities
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The slope of the line is 6, meaning that you can eliminate A,C. Since the point slope formula is y-y1=m(x-x1) you just need to see if the points are correct.
B. (3,9)
D. (1,-3)
While these do contain one point, substitute the coordinates to see which contain both.
B.
(1,-3): -3-9=6(1-3): -12=-12
(3,9): 9-9=6(9-3): 0= 6(6)
D.
(1,-3): -3+3=6(1-1): 0=6(0); 0=0
(3,9): 9+3=6(3-1): 12=6(2): 12=12
D is correct since the coordinate are on the line.
