3 years ago

How can you use functions to model linear relationships?

1 answer:

6 0

Answer:

a function is just a comparison between two quantities so when you go to plot the points, the input is x and the output is y.

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kotegsom [21]

Option 3 should be correct. Use rise over run.

5 0

3 years ago

garri49 [273]

Answer: The answer is 14

So u take the 58 to the other side and it becomes -58 so subtract 72-58 and you will get the answer for g

8 0

3 years ago

Sonja [21]

I'm not sure if you mean ( $\sqrt{x + 7}$ ) or ( $\sqrt{x} + 7$ ) I solved it both ways .

$f(x) = \sqrt{x + 7} \\ \\ f( \: g(x) \: ) = \sqrt{(8x - 11)+ 7} \\ = \sqrt{8x - 11 + 7} \\ = \sqrt{8x - 4} \\ = 2 \sqrt{2x - 1}$

____o_____o______

$f(x) = \sqrt{x} + 7 \\ \\ f( \: g(x) \: ) = \sqrt{(8x - 11)} + 7 \\ = \sqrt{8x - 11} + 7\\$

I hope I helped you^_^

8 0

3 years ago

Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

Since these two are same side interior angles, their measures must be supplementary. This means that they must add up to 180 degrees. Therefore:

45+2x-5=180

2x+40=180

2x=140

x=70

Hope this helps!

5 0

3 years ago

Reil [10]

the answer is C). y= 1/4x + 2

3 0

4 years ago