Answer:
Step-by-step explanation:
In order to make a specific shade of green paint, a painter mixes 1 1/2 quarts of blue paint. Converting 1.5 quarts to cup,
1 quart = 4 cups
1.5 quarts = 1.5 × 4 = 6 cups
She also used 1/2 gallon of white paint. Converting 0.5 gallons to cup,
0.0625 gallons = 1 cup
0.5 gallons = 0.5/0.0625 = 8 cups
This means that the ratio of cups of blue paint to green paint to white paint is 6: 2 :8
Total ratio = 6 +2 + 8 = 16
To make 100 cups of this shade of green,
Cups of blue paint needed = 6/16 × 100 = 37.5 cups
Cups of green paint needed = 2/16 × 100 = 12.5 cups
Cups of white paint needed = 8/16 × 100 = 50 cups
Slope of the function is ,Y-intercept .
The function is with initial value,Jordan puts each week andthe amount saved by Jordan after week .
To understand the slope and y-intercept lets assign as number of weeks and as the money saved by Jordan.
Jordan is already having a sum of inside the money bank so in week the amount is can be written as in coordinate form.
SImilarly
We have and
Part A:
The function is
From point-slope form,we have slope (m)
and ,plugging the values of the points.
Y-intercept of this function is the constant term or the money of that is already inside the money bank.
We can also calculate y-intercept by arranging the function as choosing any coordinate and here is the y-intercept.
The result will be same.
Part B:
The equation <u></u> can represent the function described.
And the initial value is the <u>y-intercept </u>
Jordan puts<u> </u>in his bank each week.
After week the amount saved by Jordan ,here ,as the x-variable is the number of weeks.
Plugging the value of in where so the equation becomes
So basically the function is and the amount saved by Jordan after week .
Answer:8x
2++2=4 add x up 4 = 8x
Interval [16.34 , 21.43]
First step. <u>Calculate the mean</u>
Second step. <u>Calculate the standard deviation</u>
As the number of data is less than 30, we must use the t-table to find the interval of confidence.
We have 6 observations, our level of confidence DF is then 6-1=5 and we want our area A to be 80% (0.08).
We must then choose t = 1.476 (see attachment)
Now, we use the formula that gives us the end points of the required interval
where n is the number of observations.
The extremes of the interval are then, rounded to the nearest hundreth, 16.34 and 21.43
It should be C
B is a quadratic function and A is a linear line.