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andrey2020 [161]
3 years ago
5

find the equation of a straight line passing through the point (3,3) which is perpendicular to the line y=-1/2x-4

Mathematics
1 answer:
Mars2501 [29]3 years ago
4 0

Answer:

y = 2x - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - \frac{1}{2} x - 4 ← is in slope- intercept form

with slope m = - \frac{1}{2}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-\frac{1}{2} } = 2, thus

y = 2x + c ← is the partial equation

To find c substitute (3, 3) into the partial equation

3 = 6 + c ⇒ c = 3 - 6 = - 3

y = 2x - 3 ← equation of perpendicular line

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Answer:

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Step-by-step explanation:

Solve the following system:

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Subtract 5/11 × (equation 1) from equation 2:

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Multiply equation 2 by 11/2:

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Subtract 4 × (equation 2) from equation 1:

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Divide equation 1 by 11:

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Collect results:

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