Answer:
Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}
H(X)=5.4224 bits per symb
H(X|Y="not C")=0.54902 bits per symb
Explanation:
P(B)=2P(C)
P(A)=2P(B)
But
P(A)+P(B)+P(C)=1
4P(C)+2P(C)+P(C)=1
P(C)=1/7
Then
P(A)=4/7
P(B)=2/7
Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}
iii
If X={A,B,C}
and P(Xi)={4/7,2/7,1/7}
where Id =logarithm to base 2
Entropy, H(X)=-{P(A) Id P(A) +P(B) Id P(B) + P(C) Id P(C)}
=-{(1/7)Id1/7 +(2/7)Id(2/7) +(4/7)Id(4/7)}
=5.4224 bits per symb
if P(C) =0
P(A)=2P(B)
P(B)=1/3
P(A)=2/3
H(X|Y="not C")= -(1/3)Id(I/3) -(2/3)Id(2/3)
=0.54902 bits per symb
Basic blocks are identified because they are known to be a straight line that is known also as a code sequence that tends to have no branches in regards to its in and out branches and its exception is only to the entry and at the end.
Note that Basic Block is said to be a composition of statements that is known to be one that often always executes one after other, and this is often done in a sequence.
<h3>How do you create a flow graph from the basic blocks?</h3>
Flow graph is gotten by:
- Lets Block B1 be the initial node and also Block B2 will tend to follows B1, so from B2 to B1 there is seen a kind of an edge.
Note that the first task is for a person to partition a sequence of three-address code and this is done into basic blocks.
Hence, Basic blocks are identified because they are known to be a straight line that is known also as a code sequence that tends to have no branches in regards to its in and out branches and its exception is only to the entry and at the end.
Learn more about basic blocks from
brainly.com/question/132319
#SPJ1
Answer:
<em>C++.</em>
#include <iostream>
using namespace std;
////////////////////////////////////////////////////////////////
int main() {
int weekly_hours = 0;
int hourly_rate;
float gross_pay = 0;
cout<<"Enter weekly hours worked: ";
cin>>weekly_hours;
cout<<"Enter hourly rate: ";
cin>>hourly_rate;
cout<<endl;
////////////////////////////////////////////////
if (weekly_hours > 40) {
gross_pay = (weekly_hours*hourly_rate) + ((weekly_hours*hourly_rate)*0.5);
}
else
gross_pay = weekly_hours*hourly_rate;
cout<<"Weekly gross pay: $"<<gross_pay;
////////////////////////////////////////////////
return 0;
}
Answer:
The correct answer is:
C. ndx = 0;
while (ndx < 3) {
ar[ndx] = 0;
ndx++;
}
Explanation:
The declaration given is:
int ar[3];
This means the array consists of three locations and is named as ar.
We know that the indexes are used to address the locations of an array and the index starts from 0 and goes upto to 1 less than the size of the array which means the indexes of array of 3 elements will start from 0 and end at 2.
Now in the given options we are using ndx variable to run the while loop.
So the code to assign zero to all elements of array will be
ndx = 0;
while(ndx<3)
{
ar[ndx] = 0;
ndx++;
}
Hence, the correct answer is:
C. ndx = 0;
while (ndx < 3) {
ar[ndx] = 0;
ndx++;
}
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