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grandymaker [24]
2 years ago
11

Find the solutions of the following linear equation 4 x minus 4 upon 2 = 3 upon 2​

Mathematics
1 answer:
MrRissso [65]2 years ago
4 0
U mean 4x-4^2=3^2 ? if u mean that the ans would be 6,25
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Juanita borrowed $600 to purchase a new computer. She was charged 7% interest for two years. How much interest will Juanita pay?
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Answer:

The answer is 84

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3 years ago
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Illustrative Example 1:
dlinn [17]

Given:

The data set is:

87, 84, 85, 85, 86, 90, 79, 82, 78, 76

To find:

The mode of the given data set.

Solution:

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87, 84, 85, 85, 86, 90, 79, 82, 78, 76

Arrange the data values in the ascending order.

76, 78, 79, 82, 84, 85, 85, 86, 87, 90

We know that the mode of date set is the most frequency value of the data set.

From the above data set it is clear that the number 85 has the highest frequency 2.

Therefore, the mode of the data set is 85.

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2 years ago
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Answer:

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Step-by-step explanation:

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Three exterior angles of a pentagon measures 60,80and 90.Find the measure of other two exterior angle, assuming them equally Tha
julsineya [31]

Given:

The three exterior angles of a pentagon measures 60,80 and 90.

To find:

The measure of other two exterior angle, assuming them equally.

Solution:

Let x be the measure of two other exterior angles of the pentagon.

We know that the sum of all exterior angles of a pentagon is 360 degrees.

60^\circ+80^\circ+90^\circ+x+x=360^\circ

230^\circ+2x=360^\circ

2x=360^\circ-230^\circ

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Divide both sides by 2.

\dfrac{2x}{2}=\dfrac{130^\circ}{2}

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2 years ago
The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a
Anettt [7]

Answer:

1) The size of the colony after 4 ​days is 6553 mosquitoes

2) After t = 4.9\ days

Step-by-step explanation:

To answer this question you must use the growth formula

N = N_0e ^ {kt}

Where

N_0 is the initial population of mosquitoes = 1000

t is the time in days

k is the growth rate

N is the population according to the number of days

We know that when t = 1 and N_0=1000 then N = 1600

Then we use these values to find k.

1600 = 1000e ^{k(1)}\\\\\frac{1600}{1000} = e ^ k\\\\ln(\frac{1600}{1000}) = k\\\\k = 0.47

Now that we know k we can find the size of the colony after 4 days.

N = 1000e ^ {0.47(4)}\\\\N = 6553\ mosquitoes

To know how long it should take for the population to reach 10,000 mosquitoes we must do N = 10000 and solve for t.

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6 0
3 years ago
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