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3 years ago

Whats an equation of a line thwt passes through the points (5,2) and (3,2)

Mathematics

1 answer:

Otrada [13]3 years ago

7 0

2-2=0
5-3=2

so the answer is o over 2 aka 0/2

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Simplify the following expression. 6^1/3 divided 6^10/3 (with picture)

Juli2301 [7.4K]

Answer:

The correct answer is A. 1/216

Step-by-step explanation:

Let's simplify the expression:

6^1/3 divided 6^10/3

6^1/3 = ∛ 6 and 6^10/3 = ∛ 6¹⁰, therefore:

∛ 6 / ∛ 6¹⁰

∛ 6 * 1/∛ 6¹⁰ (Flipping the reciprocal)

∛ 6 * 1/(∛ 6 * ∛ 6⁹)

1/∛ 6⁹ (Cancelling down ∛ 6 in the numerator and denominator)

1/6³ = 1/6 * 6 * 6 = 1/216

The correct answer is A. 1/216

5 0

3 years ago

⚠️HELP ASAP! (50 pts!!!)

Hatshy [7]

Answer:

137.51

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Write three different polynomial functions such that f(3) = 2.

ahrayia [7]

Answer:

1. $f (x) = x-1$

2. $f (x) = x^2-7$

3. $f (x) = x^3-25$

Step-by-step explanation:

Many polynomials can be formulated so that $f(3) = 2$ , some are as follows:

1. $f (x) = x-1$

verification:

$f (3) = 3-1 = 2$

meets the condition.

2. $f (x) = x^2-7$

verification:

$f(3)=3^2-9=9-7=2$

also meets the condition

3. $f (x) = x^3-25$

verification:

$f (3) =3^3-25=27-25 = 2$

It is also valid.

6 0

3 years ago

Samir also picks pumpkins from his garden. He picked 6 7/10 kg, but 2.6 of pumpkins were spoiled and could not be used for decor

QveST [7]

Answer:

6.7kg - 2.6kg = 4.1kg

Step-by-step explanation:

6 7/10 is equal to 6.7. If we have 6.7kg of pumpkins, but we can't use 2.6kg, then we subtract to find the amount that we can use.

7 0

2 years ago

Find the center and radius of the circle whose equation is <img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%2B%20y%5E%7B2%7D%

LenaWriter [7]

Answer:

the center is (3,1) and the radius is √6.

Step-by-step explanation:

The center of a circle can be found using the equation $(x-h)^2 + (y-k)^2 = r^2$ and is (h,k) from it. Notice h and k are the opposite value as in the equation.

First write the equation in this form.

$x^2 - 6x + ( ?)+ y^2 - 2y + (?) + 4 = 0$

Complete the square with each variable to find what numbers should go in place of the question marks.

$(-6/2)^2 = -3^2 = 9$

$(-2/2)^2 = -1^2 = 1$

Add 1 and 9 to both sides of the equation.

$x^2 - 6x + 9 + y^2 - 2y + 1 + 4 = 1 + 9\\(x-3)^2 + (y-1)^2 + 4 = 10\\(x-3)^2 + (y-1)^2 = 6$

So the center is (3,1) and the radius is √6.

4 0

3 years ago