9514 1404 393
Answer:
see attached
Step-by-step explanation:
Polynomial long division is done the way any long division is done. Find a "partial quotient", subtract from the dividend the product of that partial quotient and the divisor. The result is a new dividend. Repeat until the degree of the dividend is less than that of the divisor.
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In the attached, the "Hints" show you how the partial quotient is found, and they show you how the product of the partial quotient and divisor is found.
The partial quotient term is simply the ratio of the highest degree terms of dividend and divisor. (Unlike numerical long division, there is no guessing.)
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The remainder is the dividend of lower degree than the divisor. As in numerical long division, the full quotient expresses the remainder over the divisor.
For example, 5 ÷ 3 = 1 r 2 = 1 + 2/3.
Your full quotient is (n+5) +1/(n-6).
Answer:
m>7 = 142°
Step-by-step explanation:
m>6 = 38°
180° - 38° = 142°
m>7 = 142°
Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
Answer:
Lowest angle of the triangle with hypotenuse of 2.9ft and a leg of 2.6ft is 26.29°.
Explanation:
A triangle has a hypotenuse of 2.9ft and a leg of 2.6ft
We have smallest angle = Angle C
We have, Cos C = AC/BC
= 2.6/2.9
= 0.897
C = 26.29°
So lowest angle of the triangle with hypotenuse of 2.9ft and a leg of 2.6ft is 26.29°.