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Volgvan
3 years ago
10

PLEASE HELP ME !!!!​

Mathematics
1 answer:
Natalka [10]3 years ago
3 0

Answer:

B

Step-by-step explanation:

There are no repeating values for x, for different values plugged in for y.

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Suppose a club publishes a newsletter. Expenses are$.50 for printing and mailing each copy, plus$300 total for research and writ
luda_lava [24]

200 copies must be  sold

n= number od newsletters

0,50*n+300=2,00*n

300=1,5*n

Divide both sides by 1,5

200=n

0,50*200+300=2*200

100+300=400

400=400



5 0
3 years ago
Read 2 more answers
How do you divide (n^2-n-29)/(n-6) ??
Orlov [11]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

Polynomial long division is done the way any long division is done. Find a "partial quotient", subtract from the dividend the product of that partial quotient and the divisor. The result is a new dividend. Repeat until the degree of the dividend is less than that of the divisor.

__

In the attached, the "Hints" show you how the partial quotient is found, and they show you how the product of the partial quotient and divisor is found.

The partial quotient term is simply the ratio of the highest degree terms of dividend and divisor. (Unlike numerical long division, there is no guessing.)

__

The remainder is the dividend of lower degree than the divisor. As in numerical long division, the full quotient expresses the remainder over the divisor.

For example, 5 ÷ 3 = 1 r 2 = 1 + 2/3.

Your full quotient is (n+5) +1/(n-6).

5 0
2 years ago
Pleasee help.If anyone know 12th grade math...Please help any kind hearted ones out there​
Sidana [21]

Answer:

m>7 = 142°

Step-by-step explanation:

m>6 = 38°

180° - 38° = 142°

m>7 = 142°

3 0
3 years ago
Christopher is analyzing a circle, y^2 + x^2 = 121, and a linear function g(x). Will they intersect?
Sav [38]
Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12   (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case, 
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.

7 0
3 years ago
A triangle has a hypotenuse of 2.9ft and a leg of 2.6ft. Find the smallest angle.
OleMash [197]

Answer:

 Lowest angle of the triangle with hypotenuse of 2.9ft and a leg of 2.6ft is   26.29°.

Explanation:

 A triangle has a hypotenuse of 2.9ft and a leg of 2.6ft

 We  have smallest angle = Angle C

 We have, Cos C = AC/BC

                            = 2.6/2.9

                           = 0.897

                      C = 26.29°

So lowest angle of the triangle with hypotenuse of 2.9ft and a leg of 2.6ft is   26.29°.

8 0
3 years ago
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