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Likurg_2 [28]
3 years ago
15

PLEASE HELP ME!!!! Please show work thank you!

Mathematics
1 answer:
Vaselesa [24]3 years ago
7 0

Answer:

use khan academy

Step-by-step explanation:

khanacedemy.com

dont cheat dude

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What solid 3D object is produced by rotating the triangle about line m?
elena55 [62]

Answer: A cone with height 3 and radius 1

Step-by-step explanation:

Hi, searching I found the image for the question, attached down below.

By rotating the triangle about line m, a cone with height 3 and radius 1 is produced.

Solid 3d objects are produced by rotating a 2d figure around a straight line that lies in the same place.

in our case, if we rotate the triangle around the line, the vertices in touch with the line m remains stationary, while the  remaining vertex follows the path of a circle, creating a cone.

6 0
3 years ago
Read 2 more answers
What is the vertex of the graph of the function f(x) = x2 + 8x - 2?
vlabodo [156]

Answer:

Vertex is (-4, -18)

Step-by-step explanation:

f(x) = ax^{2} +bx +c

Let (h, k) be the vertex

An easy way to find h is to use the formula h = -b/2a

In your case where f(x) = x^{2} +8x - 2   a = 2 and b = 8

So, h =  -8/2(1) = -8/2 = -4

Substitue -4 in for x to find k

k = (-4^{2}) + 8(-4) - 2

  = (16) - 32 - 2

  = 16 - 32 - 2

  = -18

Vertex is (-4, -18)

Note:  Another way to find the vertex is to complete the square, but this can really be difficult in some cases

5 0
2 years ago
If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid
Artist 52 [7]
Check the picture below.  Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm².  Also, recall, the base is a square, thus, length = width = x.

\bf \textit{volume of a rectangular prism}\\\\&#10;V=lwh\quad &#10;\begin{cases}&#10;l = length\\&#10;w=width\\&#10;h=height\\&#10;-----\\&#10;w=l=x&#10;\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\&#10;-------------------------------\\\\&#10;\textit{surface area}\\\\&#10;S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h&#10;\\\\\\&#10;\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\&#10;-------------------------------\\\\&#10;V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3

so.. that'd be the V(x) for such box, now, where is the maximum point at?

\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2&#10;\\\\\\&#10;\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100&#10;\\\\\\&#10;x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it.  Check the second picture below.

so, the volume will then be at   \bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3

6 0
3 years ago
ASAP!!! Help me please this is due in a day! And I got so confused........ So can you guys help? By filling in the blanks(empty
Marina86 [1]

hello mai brou tenkuiusnriejqbe

4 0
2 years ago
Write a slope-intercept equation of a line that passes through (-3,4) and (3,-8)
Umnica [9.8K]
Y=-2x-2 is the right answer
4 0
3 years ago
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