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3 years ago

SIMPLE PARALLELOGRAM PERIMETER QUESTION

Mathematics

1 answer:

umka2103 [35]3 years ago

6 0

The perimeter is 62 inches. My work is shown in the picture.

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Honi is looking at a map with a scale of 1/4 in. = 20 miles. She measured the distance from Niceville to Live Oak as 2.5 in. She

expeople1 [14]

Answer:Honi made a mistake in Step 4. 50 divided by 1/4 is actually 200

4 0

3 years ago

Estimate the solution to the system of equations.

Leona [35]

Answer:

$\sf C) \ x = -1\dfrac{2}{5} , \ y = \ 1\dfrac{3}{5}$

Given equations:

a) -3x + 3y = 9

b) 2x - 7y = -14

Make x the subject in equation 1:

-3x + 3y = 9

-3x = 9 - 3y

x = y - 3

Substitute this into equation 2:

2(y - 3) - 7y = -14

2y - 7y = -14 + 6

-5y = -8

y = -8/-5

y = 1.6

Then x = y - 3

= 1.6 - 3

= -1.4

Solution: (x, y) ⇒ (-1.4, 1.6)

3 0

1 year ago

What the answer to this equation X/8+4=5 ?

V125BC [204]

Answer:

The answer to this equation is 8

Step-by-step explanation:

$\frac{x}{8} +4=5\\$

First: Subtract

$8-4=4$

$5 > 4$ meaning that 5 is greater than 4.

You still need another number to make it equal than or greater than or equal to five.

$5-4=1$

Since 5 minus 4 does equal 1

You need somewhere to divide it from to get 1 so you can add up the 4 to it and get the answer to the equation.

Lastly: Divide

$\frac{8}{8} =1$

$1+4=5\\5=5\\4\neq 5$

Now, if you do 8/8 which equals 1, 1+4 = 5; Now everything is, equaled up!

So in conclusion...

$\frac{x}{8} +4=5\\x=8\\\frac{8}{8}=1\\1+4=5\\5\neq5$

3 0

3 years ago

Read 2 more answers

a surveyor measures the distance to the two landmarks as shown in the diagram what is the distance d. between the landmarks

Inessa [10]

<h3>The distance between two landmarks is 123 meters</h3>

Solution:

We have to find the distance between two landmarks

Use the law of cosines

The third side of a triangle can be found when we know two sides and the angle between them

$c^2 = a^2 + b^2 - 2ab\ cos c$

Here, angle between 90 meters and 130 meters is 65 degrees

From figure,

a = 90

b = 130

c = d

Therefore,

$d^2 = 90^2 + 130^2 - 2(90)(130)\ cos 65\\\\d^2 = 8100 + 16900 - 23400\ cos\ 65\\\\d^2 = 25000 - 23400 \times 0.4226\\\\d^2 = 25000 - 9889.267\\\\d^2 = 15110.73\\\\d = 122.92\\\\d \approx 123$

Thus, the distance between two landmarks is 123 meters

8 0

3 years ago

HELPPP PLEASEEEE

Kryger [21]

Answer:

I think glide reflection

Step-by-step explanation:

a certain video on yt had explained the examples of similar look alike this picture

3 0

2 years ago