14 is C but I cannot see the other one
The product will not be affected by the addition of twice as much Na₂CO₃.
<h3>What is Limiting reagent in stoichiometry ?</h3>
- The maximum quantity of the end product determined by a balanced chemical equation is known as the Stoichiometry.
- The limiting reactant is the one that is consumed first and sets a limit on the quantity of product(s) that can be produced, and the one which remains unconsumed after the final reaction is in Excess.
- Calculate the moles of each reactant present and contrast it with the mole ratio of the reactants in the balanced equation to determine which reactant is the limiting one.
Here,taking the stoichiometry into consideration, we find that the reaction happens with 1:1 ratio; so, adding twice the amount of Na₂CO₃ will lead to its excess making the other the limiting reactant, hence, it would not affect the yield of the product.
To know more about the Limiting reactant, refer to:
brainly.com/question/14222359
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A water wave traveling in a straight line on a lake is described by the equation
y(x,t)=(3.75cm)cos(0.450cm?1x+5.40s?1t)
where y is the displacement perpendicular to the undisturbed surface of the lake.
Increasing reaction temperature increased the kinetic energy in the system. In fact, the <em>measurement of</em> <em>temperature </em>indirectly relates the relative amount of kinetic energy in a system.
An increase in kinetic energy results in more rapid and forceful molecular collisions, thereby increasing the rate of molecular interactions (and in a fixed-volume system, the pressure increases as well!). Hence, the reaction can occur more quickly.
Answer:
0.5 moles
Explanation:
Given data:
Number of moles of N₂O₄ = ?
Number of molecules = 3.011 × 10²³ molecules
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen
Number of moles in 3.011 × 10²³ molecules of N₂O₄.
3.011 × 10²³ molecules × 1 mol / 6.022 × 10²³ molecules
0.5 moles
