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Gnom [1K]
2 years ago
6

How many molecules are in 4HCl

Chemistry
1 answer:
Mnenie [13.5K]2 years ago
8 0
4 molecules bc the coefficient is 4
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2.54 mL of ethanol to mol ethanol (Hint: the density of ethanol is 0.789<br> g/mL.)
Katarina [22]

0.04350179862

Explanation:

Make sure to check for sig figs though. Basically, you have 2.54 mL and you multiply that by the 0.789 g/mL and mL cancels out and you are left with 2.00406g. There are 46.06844 grams per mol of ethanol, so to cancel out grams we multiply by 1/46.06844. And then we are left with 0.04350179862 mol

7 0
3 years ago
The mixture of carbon dioxide and water tastes salt why​
vampirchik [111]

Answer:

When carbon dioxide reacts with water carbonic acid is formed, from which hydrogen ions dissociate increasing the acidity of the systemCarbon dioxide emissions to the atmosphere can therefore increase the acidity of land, sea and air

Explanation:

6 0
3 years ago
Which of the following vertebrates evolved in the Carboniferous period?
topjm [15]
Reptiles arose during the Carboniferous period. Therefore making the answer Reptiles
6 0
2 years ago
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Which of the following can be measured in amps with an ammeter
alexdok [17]
I believe it is current. An ammeter is a measuring instrument used to measure the current in a circuit. Electric currents are measured in amperes (A), hence the name. Instruments used to measure smaller currents, milliampere or microampere range, are designated as milliammeters or microammeters.
8 0
3 years ago
A student puts 0.020 mol of methyl methanoate into an empty and rigid 1.0 L vessel at 450 K. The pressure is measured to be 0.74
stellarik [79]

Explanation:

Starting moles of ethanol acid = 0.020 mol

At the equilibrium 50 % of the ethanol acid molecules reacted

∴ Moles of ethanol acid reacted = 0.020 mol * 50 %/100 %

                                                                   = 0.010 mol

Moles of ethanol acid remain = 0.020 mol + 0.010 mol = 0.010 mol

Moles of the product (CH3COOH)^{2} gas formed are calculated as

0.010 mol CH3COOH * 1 mol (CH3COOH)^{2} / 2 mol CH3COOH

= 0.005 mol (CH3COOH)^{2}

Therefore at the equilibrium total moles of gas present in the vessel are 0.010 mol CH3COOH and 0.005 mol (CH3COOH)^{2}

That is total gas moles at equilibrium = 0.010 mol + 0.005 mol = 0.015 mol

Now Calculate the pressure  :

0.020 mol gas has pressure of 0.74 atm therefore at the same condition what will be the pressure exerted by 0.015 mol gas

P1/n1 = P2/n2

P2 = P1*n2 / n1

      = 0.74 atm * 0.015 mol / 0.020 mol

     = 0.555 atm

4 0
3 years ago
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