How many molecules are in 4HCl

A 50-g sample contains 32.1 g of oxygen 2 g of hydrogen and 15.9 g of carbon

Oksana_A [137]

Answer:

i need more to solve this

Explanation:

3 0

4 years ago

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In the group 3 to group 12 elements, which subshell is filled up going across the rows?

ANTONII [103]

In the group 3 to group 12 of elements, it is the d subshell that filled up going across the rows,. In the d-block of the periodic table, we have the Zinc, Cadmium, and Mercury. This corresponds to the teams 3 to 12 of the periodic table.

8 0

3 years ago

Photosynthesis takes place in what

AlexFokin [52]

The chloroplast. Chlorophyll is used for coloring, and mitochondria are energy batteries of sorts.

3 0

3 years ago

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What two conditions must be present for osmosis to occur?

siniylev [52]

Answer:

the answer is B

Explanation:

the answer is B

7 0

3 years ago

When methane (CH4) burns, it reacts with oxygen gas to produce carbon dioxide and water. The unbalanced equation for this reacti

babunello [35]

Answer:

For A: The mass of carbon dioxide produced is 0.00303 grams.

For B: The mass of water produced is 0.0025 grams.

For C: The mass of oxygen gas produced is 0.0044 grams.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For methane:

Given mass of methane = $1.10\times 10^{-3}g$

Molar mass of methane = 16 g/mol

Putting values in equation 1, we get:

$\text{Moles of methane}=\frac{1.10\times 10^{-3}g}{16g/mol}=6.875\times 10^{-5}mol$

The chemical equation for the combustion of methane follows:

$CH_4+2O_2\rightarrow CO_2+2H_2O$

For A:

By Stoichiometry of the reaction:

1 mole of methane produces 1 mole of carbon dioxide

So, $6.875\times 10^{-5}mol$ of methane will produce = $\frac{1}{1}\times 6.875\times 10^{-5}=6.875\times 10^{-5}mol$ of carbon dioxide

Now, calculating the mass of carbon dioxide from equation 1, we get:

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = $6.875\times 10^{-5}$ moles

Putting values in equation 1, we get:

$6.875\times 10^{-5}mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=(6.875\times 10^{-5}mol\times 44g/mol)=0.00303g$