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pochemuha
4 years ago
10

Explain why the graphing calculator cannot be used to solve or approximate solutions to all polynomial equations.

Mathematics
2 answers:
KATRIN_1 [288]4 years ago
5 0

Some polynomial equations have complex solutions.


Therefore, complex solutions cannot be found by graphing the related system or function in the Cartesian (x-y) plane.


Polynomial functions with all complex solutions do not have x-intercepts, and the related system of equations will not intersect.

Lelu [443]4 years ago
4 0
Let's put it this way:  If you plot a few non-x-intercept points and then draw a curvy line through them,you will not know if you got the x-intercepts even close to being correct. <span>The only way you can be sure of your x-intercepts is to set the quadratic equal to zero and solve. So its a matter of guessing from the pictures. Basicaly said, the calculator won't give you the exact result.</span>
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Answer:

f(x) = x^4 - x^3 - 7x^2 + x + 6

Step-by-step explanation:

Please, always share the instructions with every question you post.  I am assuming that you are to write out the factors corresponding to the given roots, thus constructing a 4th degree polynomial, and then performng the multiplication necesssary to produce that polynomial with terms in descending order by power of x.  Note that there must be 5 such terms.

f(x) = (x + 2)(x + 1)(x - 1)(x - 3)

Multiplying this out, we get:  

f(x) = (x + 2)(x^2 - 1)(x - 3), or

f(x) =      (x^3 - x + 2x^2 - 2)(x - 3), or:

f(x) = (x^3 + 2x^2 - x - 2)(x - 3), or:

f(x) = x^4 + 2x^3 - x^2 - 2x - 3x^3 - 6x^2 + 3x + 6

Combining like terms, we get:

f(x) = x^4 - x^3 - 7x^2 + x + 6

Note that because this is a 4th degree polynomial, the end behavior resembles that of the graph of y = x^4.  As x increases, y initially decreases in Quadrant II, passes through the y-intercept (0, 6), and then increases without bound in Quadrant I.

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Step-by-step explanation:

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