Roland has 3 paperback books and 4 hardcover books. Each hardcover book is worth $11 more than each paperback book. If the value
1 answer:
Answer:
$5
Step-by-step explanation:
Let cost of paperback book be "p"
and
Cost of hardcover book be "h"
Each hardcover is $11 more than each paperback, thus we can write:
h = p + 11
3 paperbacks at "p" each and 4 hardcovers at "h" each totals 79, thus we can write:
3p + 4h = 79
We can now put the 1st equation in 2nd equation and find "p" (cost of paperback book). Shown below:
Hence, each paperback book costs $5
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Answer: Option "B" is correct.
Step-by-step explanation:
Since we have given that
α= 0.10
Let the population variances are equal and samples are random and independent.
Let be the mean amount spent by a customer at Burger Stop.
Let be the mean amount spent by customer at Fry World.
So, it has given that
the mean amount is spent by a customer at Burger stop is greater than the mean amount spent by a customer at Fry World.
So, Hypothesis would be :
Hence, Option "B" is correct.
Complete question
The complete question is shown on the first uploaded image
Answer:
The solution and the explanation is on the second third and fourth uploaded image
complete question:
The picture below is the complete question.
Answer:
base of the triangles = 3 cm
Step-by-step explanation:
The trapezoid was broken into 2 congruent triangles and a rectangle. The 2 triangle have a height of 12 cm . The rectangle has a height of 12 cm and width of 14 cm .
The base length of the triangle can be computed as follows.
Note a congruent triangle have exactly the same three sides and exactly the same three angles.
area of a triangle = 1/2 × base × height
From the area of the trapezoid one can calculate the sides of the triangle.
area of the trapezoid = 1/2 × (a + b)h
where
a = top side
b = base side
h = height
area of the trapezoid = 1/2 × (a + b)h
area of the trapezoid = 1/2 × (14 + 20)12
area of the trapezoid = 1/2 × 34 × 12
area of the trapezoid = 34 × 6
area of the trapezoid = 204 cm²
204 = area of the triangles + area of the rectangle
204 =2 (1/2bh) + lw
where
b = base of triangle
h = height of triangle
l = length of rectangle
w = width of rectangle
204 = bh + (14 × 12)
204 = 12b + 168
12b = 204 - 168
12b = 36
divide both sides by 12
b = 36/12
b = 3 cm
base of the triangles = 3 cm
