Roland has 3 paperback books and 4 hardcover books. Each hardcover book is worth $11 more than each paperback book. If the value
1 answer:
Answer:
$5
Step-by-step explanation:
Let cost of paperback book be "p"
and
Cost of hardcover book be "h"
Each hardcover is $11 more than each paperback, thus we can write:
h = p + 11
3 paperbacks at "p" each and 4 hardcovers at "h" each totals 79, thus we can write:
3p + 4h = 79
We can now put the 1st equation in 2nd equation and find "p" (cost of paperback book). Shown below:
Hence, each paperback book costs $5
You might be interested in
Answer:
The graph is attached.
Step-by-step explanation:
The range of this data is the highest value, 22, subtracted by the lowest value, 1: 22-1 = 21.
Using boundaries, the first bar would go from 0.5-3.5; the second from 3.5-6.5; the third from 6.5-9.5; the fourth from 9.5-12.5; the fifth from 12.5-15.5; the sixth from 15.5-18.5; the seventh from 18.5-21.5; and the eighth from 21.5-24.5.
The frequency of the first bar, its height, would be 1; the height of the second bar is 2; the height of the third bar is 3; the height of the fourth bar is 2; the height of the fifth bar is 3; the height of the sixth bar is 1; the height of the seventh bar is 1; and the height of the eighth bar is 1.
