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Anika [276]
4 years ago
7

Need help asap plzz

Chemistry
1 answer:
devlian [24]4 years ago
8 0

B bend toward the middle

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Is bro2 polar or nonpolar​
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A sample of wood from the remains of a ship was found to contain 40.0% of C-14 as of ordinary wood found now. If the half-life p
kondaur [170]

Answer:

7628 y

Explanation:

Carbon-14 is radioactive and it follows the first-order kinetics for a radioactive decay. The first-order kinetics may be described by the following integrated rate law:

ln(\frac{[A]_t}{[A]_o})=-kt

Here:

[A]_t is the mass, moles, molarity or percentage of the material left at some time of interest t;

[A]_o is the mass, moles, molarity or percentage of the material initially, we know that initially we expect to have 100 % of carbon-14 before it starts to decay;

k = \frac{ln(2)}{T_{\frac{1}{2}}} is the rate constant;

t is time.

The equation becomes:

ln(\frac{[A]_t}{[A]_o})=-\frac{ln(2)}{T_{\frac{1}{2}}}t

Given:

\frac{[A]_t}{[A]_o} = \frac{40.0 %}{100.0 %}

T_{\frac{1}{2}} = 5770 y

Solve for time:

t = -\frac{ln(\frac{[A]_t}{[A]_o})\cdot T_{\frac{1}{2}}}{ln(2)}

In this case:

t = -\frac{ln(\frac{40.0\%}{100.0\%})\cdot 5770 y}{ln(2)}

t = 7628 y

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4 years ago
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dolphi86 [110]

Answer:

add more types of plants

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