idksbabgdsamh vjd,hba sh,gdk,h agshcg dhbmbkdgh ,mhfcdgs m,hdfgs kjhab ckjmhasb mhfcg asd,gbcfjkde qwhsfjasdhnf bkhjsadhgc kbasdhkfkiu ae jhbdkghaw gds hgu jidksbabgdsamh vjd,hba sh,gdk,h agshcg dhbmbkdgh ,mhfcdgs m,hdfgs kjhab ckjmhasb mhfcg asd,gbcfjkde qwhsfjasdhnf bkhjsadhgc kbasdhkfkiu ae jhbdkghaw gds hgu jidksbabgdsamh vjd,hba sh,gdk,h agshcg dhbmbkdgh ,mhfcdgs m,hdfgs kjhab ckjmhasb mhfcg asd,gbcfjkde qwhsfjasdhnf bkhjsadhgc kbasdhkfkiu ae jhbdkghaw gds hgu jidksbabgdsamh vjd,hba sh,gdk,h agshcg dhbmbkdgh ,mhfcdgs m,hdfgs kjhab ckjmhasb mhfcg asd,gbcfjkde qwhsfjasdhnf bkhjsadhgc kbasdhkfkiu ae jhbdkghaw gds hgu j
The weight of an object when calculated by multiplying with the pull of the gravity is dependent on the mass of the object and the value of g. The value of g is constant however is still dependent on the distance of the object from the center of the Earth. Thus, the answers are <em>mass and distance. </em>
The electrostatic force between two charges is inversely
proportional to the square of the distance between them.
So if you want to multiply the force by, say, ' Q ',
you need to multiply the distance by ( 1 / √Q ) .
We want to multiply the force by 16, so we need to
multiply the distance by ( 1 / √16 ) = ( 1 / 4 ) .
The distance should be changed to 1/4 of what it is now.
Explanation:
radio waves, which include visible light waves.
