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krek1111 [17]
3 years ago
9

A 10,000J battery is depleted in 2h. What power consumption is this? *

Physics
1 answer:
Tomtit [17]3 years ago
8 0

Answer:

P = 1.4 W

Explanation:

Given that,

The work done or the energy of the battery, E = 10,000 J

Time, t = 2 h

We need to find the power consumption. Let it is P. Power is the rate of doing work. So,

P=\dfrac{W}{t}\\\\P=\dfrac{10,000}{2\times 3600}\\\\P=1.38\ W

or

P = 1.4 W

So, the power of the battery is 1.4 W.

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when a hockey stick strike a hockey puck and sends it towards the goalie, (thermal, mechanical) energy is being transferred from
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Answer:

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Explanation:

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8 0
2 years ago
In a particular experiment to study the photoelectric effect, the frequency of the incident light and the temperature of the met
qwelly [4]

Answer:

B. The number of electrons emitted from the metal per second increases.

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6 0
3 years ago
This is a velocity versus time graph of a car starting from rest. If the area under the line is 10 meters, what is the correspon
adelina 88 [10]

So the area under a velocity time graph is distance or displacement, if you have done calculus yet you will understand that if you take the integral of a velocity function then you end up with displacement. Thats for later understanding however.

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8 0
3 years ago
g A loop circuit has a resistance of R1 and a current of 2 A. The current is reduced to 1.4 A when an additional 2.2 Ω resistor
Mrrafil [7]

Answer:

R1 = 5.13 Ω

Explanation:

From Ohm's law,

V = IR............... Equation 1

Where V = Voltage, I = current, R = resistance.

From the question,

I = 2 A, R = R1

Substitute into equation 1

V = 2R1................ Equation 2

When a resistance of 2.2Ω is added in series with R1,

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V = 1.4(2.2+R1)................. Equation 3

Substitute the value of V into equation 3

2R1 = 1.4(2.2+R1)

2R1 = 3.08+1.4R1

2R1-1.4R1 = 3.08

0.6R1 = 3.08

R1 = 3.08/0.6

R1 = 5.13 Ω

6 0
3 years ago
Two students below described a part of Earth's innermost layer:
Molodets [167]
The answer to your question is B- They both described the inner part otherwise known as the inner core.

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6 0
3 years ago
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