A 10,000J battery is depleted in 2h. What power consumption is this? *

Physics

1 answer:

Tomtit [17]3 years ago

8 0

Answer:

P = 1.4 W

Explanation:

Given that,

The work done or the energy of the battery, E = 10,000 J

Time, t = 2 h

We need to find the power consumption. Let it is P. Power is the rate of doing work. So,

$P=\dfrac{W}{t}\\\\P=\dfrac{10,000}{2\times 3600}\\\\P=1.38\ W$

P = 1.4 W

So, the power of the battery is 1.4 W.

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A World War II bomber flies horizontally over level terrain, with a speed of 287 m/s relative to the ground and at an altitude o

Scorpion4ik [409]

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Explanation: The attachment shows the illustration diagram for the question.

The range of the bomb's motion as obtained from the equations of motion,

H = u(y) t + 0.5g(t^2)

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That means t = √(2H/g)

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R = u(x) t = u(x) √(2H/g)

Where u(x) = the initial horizontal component of the bomb's velocity = 287 m/s, H = vertical height at which the bomb was thrown = 3.24 km = 3240 m, g = acceleration due to gravity = 9.8 m/s2

R = 287 √(2×3240/9.8) = 7380 m = 7.38 km