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Elanso [62]
3 years ago
11

Two equal groups of seedlings, and equal in height, were selected for an experiment. One group of seedlings was fed Fertilizer A

, and the other group with Fertilizer B. The mean heights of the two groups of seedlings, their standard deviations, and sample sizes are listed below. Assume simple random sampling, independence, and normally distributed data.Alpha = 0.025.Sample Mean Height (inches, Std Deviation (inches), Sample SizeFertilizer A 12.92, 0.25, 15 Fertilizer B 12.63, 0.20, 13What is the null hypothesis?a. Using the data in the previous question, what is the critical t value using the simplified textbook method and Tables when testing the claim that Fertilizer A is significantly greater than Fertilizer B? Record the answer to three decimal places (x.xxx).b.Using the data from the previous question, what is the t-statistic rounded off to one decimal place ? (x.x)c. Using the data from above, Fertilizer A is significantly greater than Fertilizer B using an alpha of 0.025?
Mathematics
1 answer:
ser-zykov [4K]3 years ago
6 0

Answer:

Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0

Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0

Here to test Fertilizer A height is greater than Fertilizer B

Two Sample T Test:

t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}

Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}

S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154

t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524

P value for Test Statistic of P(3.3524,26) = 0.0012

df = n1+n2-2 = 26

Critical value of P : t_{0.025,26}=2.05553

We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.

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alina1380 [7]
Let x be the number of treats bought
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25= 2y+x

Given that she has buys 9 pounds of dog food:

25= 2(9)+x
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With the money she has left over, she can buy 7 treats.

Hope I helped :)
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Carmen spent 88.00 at the mall the money she spent was 25% of the total amount she had in her wallet how much money did Carmen h
erastovalidia [21]

Answer:

$352

Step-by-step explanation:

x = total money she had

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4 0
2 years ago
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disa [49]
No association would be the answer.

6 0
2 years ago
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(5, 3) and (6, r) m = -1
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6 0
3 years ago
Boating: A paddleboat moves at a rate of 12 mph in still water. If the rover’s current moves at a rate of 3 mph, how long will i
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The time taken by the boat to travel 32 miles downstream is 2.1 hours and for upstream 3.56 hours.

<h3>What is speed?</h3>

Speed is defined as the ratio of the time distance traveled by the body to the time taken by the body to cover the distance.

Given that:-

  • A paddleboat moves at a rate of 12 mph in still water. If the rover’s current moves at a rate of 3 mph.
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The time taken by the boat upstream will be calculated as:-

( B + W ) Td = D

( 12 + 3 ) Td = 32

( 15 ) Td = 32

Td = 32 / 15 = 2.1 hours

The time taken by the boat downstream will be calculated as:-

( B - W ) Tu = D

( 12 - 3 ) Tu = 32

9 Tu = 32

Tu = 32 / 9 = 3.56 hours.

Therefore the time taken by the boat to travel 32 miles downstream is 2.1 hours and for upstream 3.56 hours.

To know more about Speed follow

brainly.com/question/6504879

#SPJ1

4 0
2 years ago
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