1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elanso [62]
3 years ago
11

Two equal groups of seedlings, and equal in height, were selected for an experiment. One group of seedlings was fed Fertilizer A

, and the other group with Fertilizer B. The mean heights of the two groups of seedlings, their standard deviations, and sample sizes are listed below. Assume simple random sampling, independence, and normally distributed data.Alpha = 0.025.Sample Mean Height (inches, Std Deviation (inches), Sample SizeFertilizer A 12.92, 0.25, 15 Fertilizer B 12.63, 0.20, 13What is the null hypothesis?a. Using the data in the previous question, what is the critical t value using the simplified textbook method and Tables when testing the claim that Fertilizer A is significantly greater than Fertilizer B? Record the answer to three decimal places (x.xxx).b.Using the data from the previous question, what is the t-statistic rounded off to one decimal place ? (x.x)c. Using the data from above, Fertilizer A is significantly greater than Fertilizer B using an alpha of 0.025?
Mathematics
1 answer:
ser-zykov [4K]3 years ago
6 0

Answer:

Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0

Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0

Here to test Fertilizer A height is greater than Fertilizer B

Two Sample T Test:

t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}

Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}

S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154

t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524

P value for Test Statistic of P(3.3524,26) = 0.0012

df = n1+n2-2 = 26

Critical value of P : t_{0.025,26}=2.05553

We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.

You might be interested in
5x + 2(x + 7) = 14x – 7.i will mark brainliest
Temka [501]

Answer:

5x +2x+14 =14x-7

7x+14=14x-7

14+7=14x-7x

21 divide bye 7=7x divide bye 7

3=x

Step-by-step explanation:

3 0
3 years ago
8 (1/2x -1/4) > 12-2x
Deffense [45]

Answer:

x > 7/3

Step-by-step explanation:

Distribute by 8 first

4x - 2 > 12 - 2x

6x - 2 > 12

6x > 14

x > 14/6. or x > 7/3

3 0
3 years ago
What is 7.884 rounded to the nearest hundredth
Korvikt [17]

-----------------------------

The Answer is <u><em>7.88</em></u>

-----------------------------

8 0
3 years ago
Read 2 more answers
At noon, the minute and the hour hands of a clock overlap. In how long will they again overlap?
kati45 [8]

Answer:

Okay. At noon, the hour and minute hand overlap. First, let’s calculate the speed of the hands.

The minute hand rotates once around the clock every hour. It goes 360 degrees in 60 minutes, so it rotates 360/60 or 6 degrees per minute. The hour hand goes once around the clock every 12 hours. Because there are 60 minutes in an hour, it goes 360 degrees 12*60 or 720 minutes. This means it travels at a speed of 360/720 or 0.5 degrees per minute.

Once the clock starts, the minute hand goes ahead and rotates ahead of the hour hand. At 1:00, the minute hand is at 12, and the hour hand is ahead at 1. This is where we will start our calculations.

Now, we have a variable, m, which is the minutes that have passed since the clock started. So, our minute hand speed is 6m, and our hour hand speed is 0.5m. However, because the hour hand is at one, it is at 30 degrees. (360/12 * 1.) This means our equation is 6m = 0.5m+30.

Now, we calculate.

6m = 0.5m+30

5.5m = 30

m = 30/5.5

m = 5.45

So at 5.45 minutes, the minute hand is at the hour hand. However, because one hour has passed since we started, we have to add on one hour.

So, our final total is 1 hour 5 minutes and 27 seconds.

Step-by-step explanation:

4 0
3 years ago
A 32 foot tall tree casts a shadow that is 48 feet long. How far away from the tree is a
sveticcg [70]

Answer:

39 feet

Step-by-step explanation:

take the tree as AB , the distance between the man and the tree as BC, the distance between the man and the tip of the shadow CD and the point intersecting the hypotenuse CE

since CE parallel to AB we can BPT

CE/AB = CD/BD

6/32= CD/48

CD = 9 feet

since CD is feet

BC is 48-9 = 39 feet

3 0
2 years ago
Other questions:
  • Find the length of the missing side. Leave your answer in simplest radical form.
    13·2 answers
  • Find the value of f(-4) if f(x) = x2 + 7.
    10·1 answer
  • If f(x) = x-6 and g(x)=x1/2(x+3)and g(x)Xf(x)<br> please help me
    9·1 answer
  • Phil's shadow is half as long as Phil is tall. If he were 4 inches taller and his shadow were 3 inches
    8·1 answer
  • A number increased by the quotient of 24 and the number
    10·1 answer
  • What solid shape does the two nets make?
    14·1 answer
  • You are employed as the office manager at Clover Point Pediatries, Your
    7·1 answer
  • Make a tree diagram which shows the sample space of rolling a cube with faces numbered 1-6 and flipping a fair coin. Using this
    14·1 answer
  • AREA How do you write1/2 as a percentage? Write your answer using a percent sign (%)<br>​
    11·2 answers
  • Heena has to make gift hampers out of 40 chocolates, 24 chips packets and 16 juice packets. The gift hampers have to be identica
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!