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2 years ago

A change from one state of matter to another involves the transfer of

Chemistry

2 answers:

Alja [10]2 years ago

5 0

A heat because heat is the transfer of energy.

Alja [10]2 years ago

5 0

Answer: Option (a) is the correct answer.

Explanation:

Change in state of a substance occurs due to change in position of atoms by absorption or release of heat energy.

For example, ice is the solid state of water and when we keep it at room temperature then it absorbs heat from its surroundings. As a result, intermolecular forces of attraction between its molecules weaken.

Due to this particles or atoms gain kinetic energy and they tend to move away from each other.

Thus, we can conclude that a change from one state of matter to another involves the transfer of heat.

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IRISSAK [1]

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3 years ago

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soldier1979 [14.2K]

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3 years ago

Is work done whenever you hold a heavy object for a long time?

AnnZ [28]

No, work is not done whenever you hold a heavy object for a long time

The result of a force's displacement and its component of force exerted by the object in the direction of displacement is what is known as the force's work. When we push a block with some force, the body moves quickly and work is completed.

No work, as that term is used here, is done until the object is moved in some way and a component of the force travels along the path that the object is moved. Because there is no displacement when holding a heavy object still, energy is not transferred to it.

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1 year ago

Explain how changing the concentration The enthalpy change for the reaction, 3CO (g) 2Fe2O3 (s) Imported Asset Fe(s) 3CO2 (g), c

ycow [4]

<u>Answer:</u> For the given equation, only iron has the value of $\Delta H_f$ equal to 0 kJ.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H^o$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]$

For the given chemical reaction:

$3CO(g)+2Fe_2O_3(s)\rightarrow Fe(s)+3CO_2(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(Fe(s))})+(3\times \Delta H^o_f_{(CO_2(g))})]-[(3\times \Delta H^o_f_{(CO(g))})+(2\times \Delta H^o_f_{(Fe_2O_3(s))})]$

The enthalpy of formation for the substances present in their elemental state is taken as 0.

Here, iron is present in its elemental state which is solid.

Hence, for the given equation, only iron has the value of $\Delta H_f$ equal to 0 kJ.

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3 years ago

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aliya0001 [1]

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3 years ago