Explanation:
It is given that volume is 375 mL and is 37.5 degree celsius.
First, we will calculate the mass of sample of water as it is known that density of water is 1 .
Hence, Density =
1 =
mass = 375 g
Therefore, formula to calculate heat loss will be as follows.
q = mC
where q = heat lost or absorbed
m = mass
C = specific heat of water = 4.186 J/g
= change in temperature
Hence, we will calculate value of heat lost as follows.
q = mC
= 375 g × 4.186 J/g × ( 0 - 37.5) degree celsius
= - 58865.62 joules
Thus, we can conclude that heat lost is -58865.62 joules.