All categories

3 years ago

Examine this model of an amino acid that has formed a peptide bond. What process is illustrated in this drawing?

Chemistry

2 answers:

disa [49]3 years ago

8 0

The condensation polymerization process is being demonstrated, where two molecules come together to form a larger molecule while releasing a smaller molecule, in this case water.

katen-ka-za [31]3 years ago

8 0

Answer : The process illustrated in this drawing is, condensation.

Explanation :

Amino acid : The acid that contains two functional groups that are carboxylic group, $-COOH$ and ammine group, $-NH_2$ .

When the two or more that two amino acids join together with the help of peptide bond, they produces polypeptide chain or protein.

The bond present between the two amino acid is called a peptide bond.

The peptide bond is a chemical bond that is formed between the two molecules when the nitrogen of one amino acid react with the carbon of another amino acid by releasing a water molecule. This is a dehydration synthesis or condensation reaction.

Condensation reaction : It is a reaction in which two molecules combine to form a larger molecule and producing water as a byproduct.

Hence, the process illustrated in this drawing is, condensation.

You might be interested in

Copper sulfate is a blue solid that is used to control algae growth. Solutions of copper sulfate that come in contact with the s

True [87]

Answer:

185.49 grams of Zinc would react with 454g (1lb) of copper sulfate

Explanation:

Yo know the following balanced reaction:

CuSO₄(aq)+ Zn(s) →Cu(s) + ZnSO₄(aq)

You can see that by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reagents and products are part of the reaction:

CuSO₄: 1 mole
Zn: 1 mole
Cu: 1 mole
ZnSO₄: 1 mole

Being:

Cu: 63.54 g/mole
S: 32 g/mole
O: 16 g/mole
Zn: 65.37 g/mole

the molar mass of the compounds participating in the reaction is:

CuSO₄:63.54 g/mole + 32 g/mole + 4*16 g/mole= 159.54 g/mole ≅ 160 g/mole
Zn: 65.37 g/mole
Cu: 63.54 g/mole
ZnSO₄: 65.37 g/mole + 32 g/mole + 4*16 g/mole= 161.37 g/mole

Then, by stoichiometry of the reaction, the following amounts of mass of reagent and product participate in the reaction:

CuSO₄: 1 moles* 160 g/mole= 160 g
Zn: 1 mole* 65.37 g/mole= 65.37 g
Cu: 1 mole* 63.54 g/mole= 63.54 g
ZnSO₄: 1 mole* 161.37 g/mole= 161.37 g

Now you can apply the following rule of three: if 160 grams of CuSO₄ react with 65.37 grams of Zn by this reaction stoichiometry, 454 grams of CuSO₄ with how much mass of Zn will it react?

$mass of Zn=\frac{454 grams of CuSO_{4} *65.37 grams of Zn}{160 grams of CuSO_{4}}$

mass of Zn= 185.49 grams

185.49 grams of Zinc would react with 454g (1lb) of copper sulfate

4 0

3 years ago

The part of an experiment used to compare all the other groups

Westkost [7]

Control/Control Group

3 0

3 years ago

What intermolecular force attracts two non polar molecules to each other

Salsk061 [2.6K]

The intermolecular force that attracts two nonpolar molecules is London dispersion forces, which are also called induced dipole-induced

3 0

2 years ago

The average rate of consumption of br− is 1.86×10−4 m/s over the first two minutes. what is the average rate of formation of br2

Scorpion4ik [409]

By considering the reaction equation is:
5Br(aq)+BrO3(aq)+6H(aq)= 3Br2(aq)+3H2O(l)
when the average rate of consumption of Br = 1.86x10^-4 m/s
So from the reaction equation
5Br → 3Br2 when we measure the average rate of formation (X) during the same interval So,
∴ 1.86x10^-4/5 = X / 3
∴X = 1.1 x 10^-4 m/s
∴the average rate of formation of Br2 = 1.1x10^-4 m/s

7 0

2 years ago

Calcium forms ions with a charge of +2. Iodine forms ions with a charge of -1. Which of the following would represent an ionic c

astra-53 [7]

The formula that would represent an ionic compound that is composed of calcium and iodide ions is CaI2

Explanation

Ionic compound CaI₂ is formed when Calcium form cation ( a positively charged ion) by losing 2 electrons while two iodine atoms form anion ( a negatively charged ion) by gaining one electron each.

When writing down formula of ionic compound, the formula of cation is written first followed by anion formula. therefore Ca is written first followed by I.

The numeric subscript 2 after I(iodine) indicate that 2 atoms of iodine are involved in bonding.

5 0

3 years ago