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xenn [34]
4 years ago
11

Based on the your prior knowledge, how far up a hill will a Hot Wheels car (0.01 kg) go if it is traveling at 5.0 m/s?

Physics
1 answer:
Sloan [31]4 years ago
8 0

The formula for speed id speed is equal to distance/time

so to 5.0/0.01=500m/s.

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Energy can be transformed from one form to another. The diagram shows one such process. Which energy transformation is represent
alexandr1967 [171]

The answer is A:

nuclear to thermal and radiant

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4 years ago
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Please select the word from the list that best fits the definition
slega [8]
The process by which sediment is removed from its source is called erosion.

I hope this helps :)

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4 years ago
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Shelby the Skater's rocket provides a forward force of
DochEvi [55]

Answer:

a=3.17\ m/s^2

Explanation:

Given that,

Force force acting on the Skater's rocket is 220 N

Resistive force acting on it, F' = 30 N

Mass of Shelby, m = 60 kg

We need to find the acceleration of Shelby. Net force acting on Shelby is given by :

Net force = 220-30

= 190 N

The formula of net force is :

F = ma

a is acceleration of Shelby

a=\dfrac{F}{m}\\\\a=\dfrac{190}{60}\\\\a=3.17\ m/s^2

So, the acceleration of Shelby is 3.17\ m/s^2

4 0
3 years ago
What force (in N) must be exerted on the master cylinder of a hydraulic lift to support the weight of a 2400 kg car (a large car
makvit [3.9K]

Answer:

Fm= 91.88 N

Explanation:

Pascal principle

The pressure acting on one side is transmitted to all the molecules of the liquid because the liquid is incompressible.

The pressure is definited like this:

P=F/A

Where:

P: Pressure in pascals (Pa)

F: Force acting in the area  (N)

A  : Area where the force acts  (m²)

Pascal principle

Pm=Ps

Fm/ Am= Fs/ As  Formula (1)

Where :

Pm : Pressure on the master piston

Ps  : Pressure on the slave piston

Fm : Force on the master piston (N)

Fs:  Force on the  slave piston ((N)

Am: master piston area (m²)

As:  slave piston area  (m²)

Area Formula (A)

A= π*R²

R : piston radius

Calculation of the weight of the car (W)

W= m*g= 2400 kg*9.8m/s²= 23520 N

W = Fs

Data

Fs =  23520 N

Dm = 1.5 cm

Ds = 24 cm

Rm = 0.75 cm

Rs = 12 cm

Am = π*Rm² = π*(0.75)²

As = π*Rs² = π*(12)²

Force exerted on the master cylinder

We replace data in the formula (1)

\frac{F_{m} }{A_{m} } = \frac{F_{s} }{A_{s} }

F_{m}  = \frac{F_{s}*A_{m}  }{A_{s}}

F_{m} = \frac{(23520 N)*(\pi *(0.75)^{2})(cm^{2})}{(\pi *(12)^{2})(cm^{2})}

F_{m} = (23520 N)*\frac{(0.75)^{2} }{(12)^{2} }

Fm= 91.88 N

8 0
3 years ago
Why is the Earth generally warmer at the equator than at the poles?
Elenna [48]
Because of the earths curve and temperature. The temperature in an area depends on the amount of the Sun's energy reaching the surface in that area. The equator tilts closer to the sun than the poles do. I hope this helps!
5 0
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