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vekshin1
3 years ago
12

A student uses an electronic force sensor to study how much force the student’s finger can apply to a specific location. The stu

dent uses one finger to apply a force on the sensor, and data collected from two trials are shown in the table. During which trial, if any, does the student’s finger experience the greatest electromagnetic force?
Physics
2 answers:
melisa1 [442]3 years ago
7 0

Answer:

B. Trial 2

Explanation:

Trial 2, because the student’s finger applied the largest force to the sensor.

Because the trial 2 student finger applied to largest force.

Marianna [84]3 years ago
4 0

Answer:

B. Trial 2

Explanation:

Trial 2, because the student’s finger applied the largest force to the sensor.

Because the trial 2 student finger applied to largest force.

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an electrically charged particle with mass m, velocity v, and charge q moves in a circle in magnetic field b. what is the formul
kolbaska11 [484]

Answer:

r=\frac {mv}{qb}

Explanation:

In this case,  since the charged particle moves in circular motion,  the centripetal force is equivalent to the magnetic force.

\frac {mv^{2}}{r}=qvb\\\frac {mv}{r}=qb\\r=\frac {mv}{qb}

5 0
3 years ago
Coherent light of wavelength 540 nm passes through a pair of thin slits that are 3.4 × 10-5 m apart. At what angle away from the
Scrat [10]

Answer: 1.8\°

Explanation:

The diffraction angles \theta_{n} when we have a slit divided into n parts are obtained by the following equation:

dsin\theta_{n}=n\lambda (1)

Where:

d=3.4(10)^{-5}m is the width of the slit

\lambda=540 nm=540(10)^{-9}m is the wavelength of the light  

n is an integer different from zero.

Now, the second-order diffraction angle is given when n=2, hence equation (1) becomes:

dsin\theta_{2}=2\lambda (2)

Now we have to find the value of \theta_{2}:

sin\theta_{2}=\frac{2\lambda}{d} (3)

Then:

\theta_{2}=arcsin(\frac{2\lambda}{d})   (4)

\theta_{2}=arcsin(\frac{2(540(10)^{-9}m)}{3.4(10)^{-5}m})   (5)

Finally:

\theta_{2}=1.8\°   (6)

5 0
3 years ago
What are the units of radiation?
Ksenya-84 [330]

The radiation dose absorbed by a person is measured using the conventional unit rad or the SI unit gray. The biological risk of exposure to radiation is measured using the conventional unit rem or the SI unit sievert.

I hope this helps!

3 0
2 years ago
John says that the value of the function cos[ω(t + T) + ϕ], obtained one period T after time t, is greater than cos(ωt + ϕ) by 2
Svetllana [295]

Answer:

No one is right

Explanation:

John Case:

The function cos(\omega t +\phi) is defined between -1 and 1, So it is not possible obtain a value 2\pi greater.  

In addition, if you  move the function cosine a T Value, and T is the Period,  the function take the same value due to the cosine is a periodic function.

Larry case:

Is you have f=1+cos(\omega t +\phi), the domain of this is [0,2].

it is equivalent to adding 1 to the domain of the f=1+cos(\omega t +\phi), and its mean that the function f=cos(\omega t +\phi), in general, is not greater than cos(\omega t +\phi).

3 0
3 years ago
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