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4 years ago

12

A student uses an electronic force sensor to study how much force the student’s finger can apply to a specific location. The stu

dent uses one finger to apply a force on the sensor, and data collected from two trials are shown in the table. During which trial, if any, does the student’s finger experience the greatest electromagnetic force?

2 answers:

melisa1 [442]4 years ago

7 0

Answer:

B. Trial 2

Explanation:

Trial 2, because the student’s finger applied the largest force to the sensor.

Because the trial 2 student finger applied to largest force.

Marianna [84]4 years ago

4 0

Answer:

B. Trial 2

Explanation:

Trial 2, because the student’s finger applied the largest force to the sensor.

Because the trial 2 student finger applied to largest force.

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The tub of a washing machine goes into its spin cycle, starting from rest and gaining angular speed steadily for 6.00 s, at whic

MatroZZZ [7]

Answer:

$N = 42 rev$

Explanation:

As we know that initial angular speed of the tub was zero and then it increases uniformly to 4 rev/s in t = 6.00 s

so we will have

$\theta_1 = \frac{\omega_f + \omega_i}{2} t$

$\theta_1 = \frac{2\pi f_2 + 2\pi f_1}{2}(t)$

$\theta_1 = \frac{2\pi \times 4 + 0}{2}(6)$

$\theta_1 = 75.4 rad$

Now when the tub will comes to rest uniformly after opening the lid in time interval of t = 15 s

then we have

$\theta_2 = \frac{\omega_f + \omega_i}{2} t$

$\theta_2 = \frac{2\pi f_2 + 2\pi f_1}{2}(t)$

$\theta_2 = \frac{2\pi \times 4 + 0}{2}(15)$

$\theta_2 = 188.5 rad$

Now total angular displacement of the tub is given as

$\theta = \theta_1 + \theta_2$

$\theta = 75.4 + 188.5$

$\theta = 263.9 rad$

so number of revolutions is given as

$\N = \frac{\theta}{2\pi}$

$N = 42 rev$

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3 years ago

7. A runner runs on the track field with a velocity of 20 m/s and it is known that her momentum is

Dennis_Churaev [7]

Answer:

Weight of the runner is 60 kilograms

Explanation:

Momentum is the product of weight and velocity.

The formula is : p=mv where m is mass in kg and v is velocity in m/s

Given in the question ;

v= 20 m/s and p=1200 kg*m/s

Applying the formula as;

p= mv

1200 = m * 20

1200/20 = m

60 kg = m

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3 years ago

What must a magnet always have?

Rainbow [258]

Answer:

two opposite poles

Explanation:

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3 years ago

Read 2 more answers

Milk with a density of 1020 kg/m3 is transported on a level road in a 9-m-long, 3-m-diameter cylindrical tanker. The tanker is c

jeka57 [31]

Solution :

Given data is :

Density of the milk in the tank, $\rho = 1020 \ kg/m^3$

Length of the tank, x = 9 m

Height of the tank, z = 3 m

Acceleration of the tank, $a_x = 2.5 \ m/s^2$

Therefore, the pressure difference between the two points is given by :

$P_2-P_1 = -\rho a_x x - \rho(g+a)z$

Since the tank is completely filled with milk, the vertical acceleration is $a_z = 0$

$P_2-P_1 = -\rho a_x x- \rho g z$

Therefore substituting, we get

$P_2-P_1=-(1020 \times 2.5 \times 7) - (1020 \times 9.81 \times 3)$

$=-17850 - 30018.6$

$=-47868.6 \ Pa$

$=-47.868 \ kPa$

Therefore the maximum pressure difference in the tank is Δp = 47.87 kPa and is located at the bottom of the tank.

4 0

3 years ago

An airline executive decides to economize by reducing the amount of fuel required for long-distance flights. He orders the groun

Makovka662 [10]

Answer

given,

mass of paint removed from the airline = 100 Kg

a) altitude of the airplane = 12000 m

energy saved to not to lift the plane = ?

U = m g h

U = 100 x 9.8 x 12000

U = 117.6 x 10⁵ J

U = 1.18 x 10⁷ J

b) Speed of the airplane = 250 m/s

$U = \dfrac{1}{2}mv^2$

$U = \dfrac{1}{2}\times 100 \times 250^2$

U =31.25 x 10⁵ J

U = 3.125 x 10⁶ J

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3 years ago