Answer: The electric field is: a) r<a , E0=; b) a<r<b E=ρ (r-a)/εo;
c) r>b E=ρ b (b-a)/r*εo
Explanation: In order to solve this problem we have to use the Gaussian law in diffrengios regions.
As we know,
∫E.dr= Qinside/εo
For r<a --->Qinside=0 then E=0
for a<r<b er have
E*2π*r*L= Q inside/εo in this case Qinside= ρ.Vol=ρ*2*π*r*(r-a)*L
E*2π*r*L =ρ*2*π*r* (r-a)*L/εo
E=ρ*(r-a)/εo
Finally for r>b
E*2π*r*L =ρ*2*π*b* (b-a)*L/εo
E=ρ*b* (b-a)*/r*εo
Answer:
Zero
Explanation:
Given the equation of an ellipse:
The eccentrity of an ellipse is given by:
For a circle, we have
Therefore the eccentricity of a circle is
Answer:
Thank you so much.
Explanation:
Please give me brainliest :) I will greatly appreciate it :D
Answer:
like horror? or action haha
Explanation:
Answer:
Option C
Explanation:
From the question we are told that:
Mass 
Radius 
Time 
Generally the equation for Tension is mathematically given by
Therefore
, toward the center of the circle
Option C
