Answer:
The distance traveled by the skier is 5.309 km
Solution:
As per the question:
Mass of the skier, m = 64 kg
Coefficient of friction between the ski and the snow, 
Mass of snow, M = 5.0 kg
Now,
To calculate the distance, 's' traveled by the skier, in order to melt 5.0 kg of snow:
We know that:
where
= coefficient of friction
N = Normal Reaction
N = mg
Thus
(1)
Also,
(2)
where
= Latent Heat of fusion
Thus from eqn (1) and (2):
s = 5.309 km
Answer:
Her friend disagrees because the biologist is not working with nanotechnology which would enable her to be a nanotechnologist.
The biologist is only working with nano antibodies.
The car will move in a speed of 45 meter per second
Answer:
a)
v = 14.1028 m/s
∅ = 83.0765° north of east
b)
the required distance is 40.98 m
Explanation:
Given that;
velocity of the river u = 1.70 m/s
velocity of boat v = 14.0 m/s
Now to get the velocity of the boat relative to shore;
( north of east), we say
a² + b² = c²
(1.70)² + (14.0)² = c²
2.89 + 196 = c²
198.89 = c²
c = √198.89
c = 14.1028 m/s
tan∅ = v/u = 14 / 1.7 = 8.23529
∅ = tan⁻¹ ( 8.23529 ) = 83.0765° north of east
Therefore, the velocity of the boat relative to shore is;
v = 14.1028 m/s
∅ = 83.0765° north of east
b)
width of river = 340 m,
ow far downstream has the boat moved by the time it reaches the north shore in meters = ?
we say;
340sin( 90° - 83.0765°)
⇒ 340sin( 6.9235°)
= 40.98 m
Therefore, the required distance is 40.98 m
Potential energy due to gravity
