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Galina-37 [17]
3 years ago
11

Please help me with this question. ill mark you brainlist or whatever you want.

Physics
2 answers:
Bad White [126]3 years ago
8 0

Answer:

Good:

Quarrying creates jobs in areas where there are limited opportunities.

There is a huge demand for the products of quarrying, such as building stone and cement. ...

Quarrying provides income to local councils through taxation.

Good communications are needed for transporting the products of quarrying.

Bad: Quarrying creates pollution from noise and dust.

Heavy traffic causes pollution and congestion on narrow country roads. ...

Quarries create visual pollution and tourists may be deterred by the scars on the landscape.

Explanation:

Tanya [424]3 years ago
4 0

Answer:

fdhjyegshdrhjfsdffddfnfdhdfkjdfkjkjdfijldfjkdfndfkjhdfbhjfdjdfhhjdfhj

Explanation:

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Explain why an object’s weight is dependent upon where in the universe it is located.
strojnjashka [21]

Answer:

The weight of any object will depend on its location in the universe, commanded by the law of gravitacion universal de Newton

Explanation:

Everything obeys the law of universal gravity proposed by Newton. Where the attraction force with which one body attracts another depends on the mass of the body that attracts the body with less mass, the radius of the body with the greatest mass and the universal gravitational constant.

For a better understanding of this concept let us use examples with numeric values. In the first example we will determine with what force planet Earth attracts a person of 70 [kg].

And in the second example we will perform the same exercise but on a planet like Jupiter

Example 1:

A person with a mass of 70 [kg] is located on planet Earth which has a mass of 5.97x10^24 [kg] and a terrestrial radius of 6371 [km]. Find the force exerted by the planet upon the person.

We have the  law of universal gravity

F=G*\frac{m_{1} *m_{2} }{r^{2} } \\where\\G = 6.67*10^-11[\frac{N*m^{2} }{kg^{2}} ]\\m_{1}=70[kg]\\m_{2}=5.97*10^{24} [kg]\\r= 6371[km]

Now replacing the values in the equation we have:

F=6.67*10^{-11} *\frac{70*5.97*10^{24} }{(6371*10^3)^{2} } \\F=687[N]

We can appreciate that if we only use the terms of mass of the earth, the gravitational constant and the radius of the earth, we will have the value of the gravity accelaration of the earth. Let's check

g_{earth} =6.67*10^{-11} *\frac{5.97*10^{24} }{(6371*10^3)^{2} } \\g_{earth} = 9.81 [m/s^{2} ]

Example 2:

A person with a mass of 70 [kg] is located on planet Jupiter which has a mass of 1.899x10^27 [kg] and a  radius of 71492 [km]. Find the force exerted by the planet upon the person.

F=6.67*10^{-11}*\frac{70*1.899*10^{27} }{(71492*10^3)^{2} }  \\F= 1734.73[N]

We will calculate the value of the gravity accelaration of Jupiter. Let's check

g_{jupiter} = 6.67*10^{-11} *\frac{1.899*10^{27} }{(71492*10^3)^{2} } \\g_{jupiter}= 24.8 [m/s^2]\\

Therefore an object in jupiter will weigh more than 2.5 times its weight than on planet Earth.

We found that the force of attraction or the weight of any object will depend on its location in the universe, commanded by the law of gravitacion universal de Newton

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1) ironing a shirt 2) writing on surfaces 3) working of an eraser

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