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Sergeeva-Olga [200]
3 years ago
7

Trying to think about this

Mathematics
1 answer:
Ronch [10]3 years ago
6 0
The answer is D. 160
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If f(x)=6x^2 and g(x)=14x + 4 solve (g o f)(2)<br> Choices:<br> 340<br> 465<br> 336<br> 284
Law Incorporation [45]

The answer is 340

Explanation:

(g o f)(2) = g(f(2))

f(2) = 6(2)² = 24

g(f(2)) = g(24) = 14(24) + 4 = 336 + 4 = 340

8 0
3 years ago
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Please make Y=x+12 and 4x+2y=27 into one equation.
tiny-mole [99]
So what you need to start with is taking the x from both sides as adding 12 to them. Then, you move the 27 over 4 decimals.
4 0
2 years ago
What is x? Please help fast
maks197457 [2]

Answer:

72

Step-by-step explanation:

180-108

5 0
3 years ago
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840/1152 simplified please ​
Nina [5.8K]

\bf  \frac{840}{1152}^{(4}  =  \frac{210}{288}^{(6}  =  \frac{35}{48}

8 0
2 years ago
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What is the equation of a quadratic function p with rational coefficients that has a zero of 3-i
Kryger [21]

Answer:

p = x² − 6x + 10

Step-by-step explanation:

Complex roots come in conjugate pairs.  So if 3−i is a root, then 3+i is also a root.

p = (x − (3−i)) (x − (3+i))

p = x² − (3+i)x − (3−i)x + (3−i)(3+i)

p = x² − 3x − ix − 3x + ix + (9 − i²)

p = x² − 6x + 10

You can check your answer using the quadratic formula.

x = [ -b ± √(b² − 4ac) ] / 2a

x = [ 6 ± √(36 − 40) ] / 2

x = (6 ± 2i) / 2

x = 3 ± i

6 0
3 years ago
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