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KIM [24]
3 years ago
5

Given a very unusual cell with an intracellular fluid containing 1 mM calcium phosphate and an extracellular fluid containing 10

0 mM calcium phosphate. If the cell membrane contains open ion channels that are permeable only to calcium ions, what is the membrane potential (Vm) when the system attains equilibrium
Biology
1 answer:
vladimir1956 [14]3 years ago
8 0

Answer:

M.P = 140.46 Vm

Explanation:

Membrane potential can calculated using the following equation:

<em>(61/z) ln ([X]out/[X]in)</em>

where z is the charge of Ca2+ ion and X represent the concentrations By applying necessary calculations…

Membrane potential = (61 / 2) ln (100 x 10^-3 / 1 x 10^-3)

                                  = 30.5 x 4.60 = 140.46 Vm

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Hope this helps :3

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