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3 years ago

The acceleration means that for each second that passes, falling objects move 9.8 meters.

Physics

1 answer:

lisabon 2012 [21]3 years ago

5 0

Answer:

B. False

Explanation:

An acceleration of 9.8 m/s² means the velocity increases by 9.8 m/s every second.

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The fundamental frequency of a guitar string is 367 hz . part a what is the fundamental frequency if the tension in the string i

ANTONII [103]

The fundamental frequency of a string is given by:
$f_1 = \frac{1}{2L} \sqrt{ \frac{T}{\mu} }$
where L is the string's length, T the tension and $\mu$ the linear density of the string.

We can see that f1 is proportional to the square root of T: $\sqrt{T}$ .
This means that if the new tension is half the initial value, the new fundamental frequency will be proportional to $\sqrt{ \frac{T}{2} }= \frac{ \sqrt{T} }{ \sqrt{2} }= \frac{f_1}{ \sqrt{2} }$

So, the new fundamental frequency will be
$f_1 ' = \frac{367 Hz}{ \sqrt{2} }=259.5 Hz$

6 0

4 years ago

A sinusoidal wave travels along a stretched string. A particle on the string has a maximum speed of 2.0 m/s and a maximum accele

JulsSmile [24]

Answer:

The amplitude of the wave is 0.02 m.

Explanation:

Given that,

Maximum speed = 2.0 m/s

Maximum acceleration = 200 m/s²

We need to calculate the angular frequency

Using formula of angular frequency

$\omega=\dfrac{a_{max}}{v_{max}}$

Put the value into the formula

$\omega=\dfrac{200}{2.0}$

$\omega=100\ rad/s$

We need to calculate the amplitude of the wave

Using formula of velocity

$v_{max}=A\omega$

$A=\dfrac{v_{max}}{\omega}$

Put the value into the formula

$A=\dfrac{2.0}{100}$

$A=0.02\ m$

Hence, The amplitude of the wave is 0.02 m.

8 0

4 years ago

On a recent adventure trip, Anita Break went rock-climbing. Anita was able to steadily lift her 800- kg body 20.0 meters in 100

Irina-Kira [14]

Answer:

Anita 's power rating during this portion of the climb is 1568 Watts.

Explanation:

Given that,

Mass of the body, m = 800 kg

Height, h = 20 m

Time, t = 100 s

We need to find the Anita 's power rating during this portion of the climb. Power rating of an object is given by the work done per unit time. It is given by :

$P=\dfrac{W}{t}$

$P=\dfrac{mgh}{t}$

$P=\dfrac{800\times 9.8\times 20}{100}$

P = 1568 Watts

So, Anita 's power rating during this portion of the climb is 1568 Watts. Hence, this is the required solution.

6 0

3 years ago

Am I correct? Plz answer ASAP! I will give brainilest:D (Science)

aivan3 [116]

Answer:

I would agree with your selection.

Explanation:

3 0

3 years ago

2) A 20 kg mass moving at a speed of 3 m/s is stopped by a constant force of 15 N. How many seconds must the force act on the ma

hammer [34]

Take the object's starting direction of motion to be the positive direction, so that a stopping force acts in the opposite direction. By Newton's second law, the object undergoes an acceleration a such that

-15 N = (20 kg) a

Solve for a :

a = - (15 N) / (20 kg) = -0.75 m/s²

The object's velocity v at time t is then given by

v = 3 m/s + (-0.75 m/s²) t

so the time it takes for the object to slow to a rest is

0 = 3 m/s + (-0.75 m/s²) t

t = (3 m/s) / (0.75 m/s²) = 4.0 s

3 0

3 years ago