Answer:0.302
Explanation:
Given
mass of crate m=27 kg
Force required to set crate in motion is 80 N
Once the crate is set in motion 56 N is require to move it with constant velocity
i.e. 80 N is the amount of force needed to just overcome static friction and 56 is the kinetic friction force
thus

where
is the coefficient of static friction and N is Normal reaction





1) 0.0011 rad/s
2) 7667 m/s
Explanation:
1)
The angular velocity of an object in circular motion is equal to the rate of change of its angular position. Mathematically:

where
is the angular displacement of the object
t is the time elapsed
is the angular velocity
In this problem, the Hubble telescope completes an entire orbit in 95 minutes. The angle covered in one entire orbit is
rad
And the time taken is

Therefore, the angular velocity of the telescope is

2)
For an object in circular motion, the relationship between angular velocity and linear velocity is given by the equation

where
v is the linear velocity
is the angular velocity
r is the radius of the circular orbit
In this problem:
is the angular velocity of the Hubble telescope
The telescope is at an altitude of
h = 600 km
over the Earth's surface, which has a radius of
R = 6370 km
So the actual radius of the Hubble's orbit is

Therefore, the linear velocity of the telescope is:

The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value.
Answer:
E = -4000 N / C
Explanation:
The potential and electric field are related
V = - E s
E = - V / s
we reduce the magnitudes to the SI system
s = 4 mm (1 m / 1000 mm) = 0.004 m
we calculate
E = - 16 /0.004
E = -4000 N / C
Three basic types of population distribution within a regional range are (from top to bottom) uniform, random, and clumped.