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Temka [501]
3 years ago
5

Jennifer is making a collage using her favorite photos. She wants to cover the collage with something that allows her to see the

photos, but also protects them from dust. Which material should Jennifer use?
a material that absorbs light
a transparent material
an opaque material
a material that reflects light
Physics
2 answers:
Neko [114]3 years ago
7 0

Answer: a transparent material

Explanation:

Materials that do not transmit light are known as opaque objects. These objects absorb all the light.

Transparent material transmit all the light. Thus, we can see through the transparent material. So, Jennifer must cover the collage with a transparent material that allows her to see photos thereby protecting them from dust.

Karolina [17]3 years ago
4 0
B.) A transparent material
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How has technology influenced theories over time?
Contact [7]
Better technology is helping us because we can see more stuff like the microscope we able to make assumptions based on what we saw.  
7 0
4 years ago
A constant force of 45 N directed at angle θ to the horizontal pulls a crate of weight 100 N from one end of a room to another a
Rasek [7]

Answer:

W=173.48J

Explanation:

information we know:

Total force: F=45N

Weight: w=100N

distance: 4m

vertical component of the force: F_{y}=12N

-------------

In this case we need the formulas to calculate the components of the force (because to calculate the work we need the horizontal component of the force).

horizontal component: F_{x}=Fcos\theta

vertical component: F_{y}=Fsen\theta

but from the given information we know that F_{y}=12N

so, equation these two F_{y}=Fsen\theta and F_{y}=12N

Fsen\theta =12N

and we know the force F=45N, thus:

45sen\theta=12

now we clear for \theta

sen\theta =12/45\\\theta=sin^{-1}(12/45)\\\theta =15.466

the angle to the horizontal is 15.466°, with this information we can calculate the horizontal component of the force:

F_{x}=Fcos\theta

F_{x}=45cos(15.466)\\F_{x}=43.37N

whith this horizontal component we calculate the work to move the crate a distance of 4 m:

W=F_{x}*D\\W=(43.37N)(4m)\\W=173.48J

the work done is W=173.48J

7 0
3 years ago
A water bath in a physical chemistry lab is 1.55 m long, 0.710 m wide, and 0.570 m deep (high). If it is filled to within 3.55 i
Lesechka [4]

Answer:

528 liter.

Explanation:

Volume of the tank(cuboid) = l*b*h

But volume of the water = l*b*h

Where

l= length of the tank

b = width of the tank

h = the length from the bottom of the tank,

3.55 in to m,

0.09017m

Length of the water in the tank = 0.570 - 0.09017

= 0.47983 m.

Volume = 0.47983*0.710*1.55

= 0.528 m3.

1 m3 = 1000 liter.

0.528 m3 = 0.528*1000

= 528 liter

7 0
3 years ago
If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string
vovikov84 [41]

Complete Question

The speed of a transverse wave on a string of length L and mass m under T is given by the formula

     v=\sqrt{\frac{T}{(m/l)}}

If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string

Answer:

(m/l)=\frac{10}{V^2}

Explanation:

From the question we are told that

Speed of a transverse wave given by

v=\sqrt{\frac{T}{(m/l)}}

Maximum Tension is T=10.0N

Generally making (m/l) subject from the equation mathematically we have

v=\sqrt{\frac{T}{(m/l)}}

v^2=\frac{T}{(m/l)}

(m/l)=\frac{T}{V^2}

(m/l)=\frac{10}{V^2}

Therefore the Linear mass in terms of Velocity is given by

(m/l)=\frac{10}{V^2}

8 0
3 years ago
An airtight box has a removable lid of area 1.00 10-2 m2 and negligible weight. the box is taken up a mountain where the air pre
gladu [14]
<span>9.50x10^2 newtons A pascal is defined as 1 newton per square meter. So let's multiply the pressure by the surface area of the box lid. F = 1.00x10^-2 m^2 * 9.50x10^4 N/m^2 = 9.50x10^2 N So it will take 9.50x10^2 newtons of force to remove the lid from the box.</span>
8 0
3 years ago
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