Answer:
Explanation:
T₁ = 700 + 273 = 973 k
T₂ = 330 + 273 = 603 k
Theoretical efficiency = T₁ - T₂ / T₁
= (973 - 603) / 973
= .38 OR 38%
Operating efficiency = .79 x 38
= 30.02 %
Heat input Q₁ , Heat output to sink Q₂ , conversion into power = Q₁ - Q₂
given Q₁ - Q₂ = 1.3 x 10⁹ W
efficiency = Q₁ - Q₂ / Q₁
Q₁ - Q₂ / Q₁ = 30.02 / 100
100Q₁ - 100Q₂ = 30.02Q₁
69.98 Q₁ = 100Q₂
Q₁ = 1.429 Q₂
Putting this in the relation
Q₁ - Q₂ = 1.3 x 10⁹ W
1.429Q₂ - Q₂ = 1.3 x 10⁹ W
.429Q₂ = 1.3 x 10⁹
Q₂ = 3.03 x 10⁹W
= 3.03 GW.
Answer: a) 456.66 s ; b) 564.3 m
Explanation: The time spend to cover any distance a constant velocity is given by:
v= distance/time so t=distance/v
The slower student time is: t=780m/0.9 m/s= 866.66 s
For the faster students t=780 m/1,9 m/s= 410.52 s
Therefore the time difference is 866.66-410.52= 456.14 s
In order to calculate the distance that faster student should walk
to arrive 5,5 m before that slower student, we consider the follow expressions:
distance =vslower*time1
distance= vfaster*time 2
The time difference is 5.5 m that is equal to 330 s
replacing in the above expression we have
time 1= 627 s
time2 = 297 s
The distance traveled is 564,3 m
Heat flow occurs when two systems in contact are not at the same temperature.
What is heat flow?
- when two bodies of different temperatures are in contact, heat flow takes place.
- Heat flows till the two bodies in contact achieve equilibrium.
- To achieve equilibrium, heat flows from hotter bodies to colder bodies.
- There is no heat flow after achieving the state of equilibrium because the amount of heat flow from one body to the other is the same.
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It can't be less than 250 N or the cart wouldn't move at all. That means there is only 1 answer. It's between not enough info or 250 N. The answer is 250 N. If it was any more, there would be acceleration.
