It would use rapid combustion
Answer:
Number of protons and neutrons
Option (a) is correct,
the purpose of the condenser is to de-superheat, the entering vapor, condense the vapor to a liquid, and subcool the liquid.
<h3>What is a condenser's purpose?</h3>
A condenser uses a cooling fluid to attempt to sufficiently cool down a vapor, changing its state from a vapor to a liquid. Condensers come in a variety of designs, including direct condensing, which involves coming into direct touch with the cooling fluid and the vapor.
<h3>What kind of vapor is condensed?</h3>
The vapour that needs to condense might be highly different and can even include non-condensable vapour, such as air, which greatly affects how well the condenser works.
Learn more about condenser here:-
brainly.com/question/12138870
#SPJ4
The reaction of sugar with oxygen is as follows:
C₁₂H₂₂O₁₁ + 12 O₂ → 12 CO₂ + 11 H₂O
When in the presence of pure oxygen, sucrose (table sugar) will not form caramel, in fact it will combust into carbon dioxide and water like any other carbohydrate.
Caramel is actually formed by slowly heating sucrose to high temperatures of around 170 °C resulting in thermal decomposition. This essentially removes molecules of water from the sucrose which results in the compound isomerizing and eventually polymerizing to form caramel. The chemical make up of caramel is the same as sucrose, so it will still be composed of carbon, hydrogen and oxygen.
Answer:
16.2 J
Explanation:
Step 1: Given data
- Specific heat of liquid bromine (c): 0.226 J/g.K
- Volume of bromine (V): 10.0 mL
- Initial temperature: 25.00 °C
- Final temperature: 27.30 °C
- Density of bromine (ρ): 3.12 g/mL
Step 2: Calculate the mass of bromine
The density is equal to the mass divided by the volume.
ρ = m/V
m = ρ × V
m = 3.12 g/mL × 10.0 mL
m = 31.2 g
Step 3: Calculate the change in the temperature (ΔT)
ΔT = 27.30 °C - 25.00 °C = 2.30 °C
The change in the temperature on the Celsius scale is equal to the change in the temperature on the Kelvin scale. Then, 2.30 °C = 2.30 K.
Step 4: Calculate the heat required (Q) to raise the temperature of the liquid bromine
We will use the following expression.
Q = c × m × ΔT
Q = 0.226 J/g.K × 31.2 g × 2.30 K
Q = 16.2 J
