Answer:
Q = 3440Kj
Explanation:
Given data:
Mass of gold = 2kg
Latent heat of vaporization = 1720 Kj/Kg
Energy required to vaporize 2kg gold = ?
Solution:
Equation
Q= mLvap
It is given that heat required to vaporize the one kilogram gold is 1720 Kj thus, for 2 kg
by putting values,
Q= 2kg × 1720 Kj/Kg
Q = 3440Kj
In regards to the given question, option “1” is the correct
option. When propane is burnt to complete combustion, it results in the
formation of two completely different substances. It actually forms a mixture
of water vapour and carbon dioxide. When NaCl or sodium chloride is melted, it
does not result in the formation of any new substance and so option “2” cannot
be the correct answer. With regards to deposition of carbon dioxide and solidification
of water, no new substance gets formed and so can be neglected as the answer to
the question.
rxns is an abbreviation for reactions
Answer:
C) Steam condensing on a mirror
Explanation:
This was just a change in the physical state.
