Answer:
The probability that the candidate score is 600 or greater
P(X≥ 600 ) = 0.0228
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
Given mean of the Population = 500
Given standard deviation of the Population = 50
Let 'X' be the random variable in normal distribution
Given X = 600

<u><em>Step(ii)</em></u>:-
The probability that the candidate score is 600 or greater
P(X≥ 600 ) = P(z≥2)
= 0.5 - A(2)
= 0.5 -0.4772
= 0.0228
<u><em>Final answer</em></u>:-
The probability that the candidate score is 600 or greater
P(X≥ 600 ) = 0.0228
You multiply those and you get d = 325 m
Step-by-step explanation:
Let, 1st number be x and 2nd number be y
Then,
equation 1
x = 16+y
equation 2
x + y = 120
or, y = 120 - x
now,
x = 16 + y
or, x= 16 + 120 - x (putting the value of y from equation 2 )
or, x + x = 136
or, 2x =136
or, x= 136/2
or, x =68
Then,
y = 120-x
or, y= 120- 68 (putting the value of x)
or, y= 52
Hence, the two numbers are 68 and 52.
Answer:A
Step-by-step explanation:hole this helps
#1 is 60\100 which can be reduced to 3\5