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The solutions of the quadratic equation x² - 5x - 36 = 0 are -4 and 9.
The graph is attached below.
- We are given a quadratic function.
- A polynomial equation of degree two in one variable is a quadratic equation.
- The function given to us is :
- y = x² - 5x - 36
- We need to find the solution of the quadratic function.
- To find the roots, let y = 0.
- x² - 5x - 36 = 0
- Use the quadratic formula.
- In elementary algebra, the quadratic formula is a formula that gives the solution(s) to a quadratic equation.
- x = [-b±√b²-4ac]/2a
- x = [-(-5) ± √25 - 4(1)(-36)]/2(1)
- x = (5 ± √25 + 144)/2
- x = (5 ± √169)/2
- x = (5 ± 13)/2
- x = 9 or x = -4
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Answer:
see explanation
Step-by-step explanation:
(1)
Since FE = FG the triangle is isosceles with ∠ E = ∠ G, then
∠ E = =
= 37°
(2)
Since all 3 sides are congruent then triangle is equilateral with the 3 angles being congruent, 60° each , then
12y = 60 ( divide both sides by 12 )
y = 5
(3)
The 3 angles are congruent then triangle is equilateral with the 3 sides being congruent, then
KL = JL , that is
4t - 8 = 2t + 1 ( subtract 2t from both sides )
2t - 8 = 1 ( add 8 to both sides )
2t = 9 ( divide both sides by 2 )
t = 4.5
(4)
Given ∠ B = ∠ C then triangle is isosceles with 2 legs being congruent , that is
AB = AC
4x + 1 = 9 ( subtract 1 from both sides )
4x = 8 ( divide both sides by 4 )
x = 2
Then
perimeter = AB + BC + AC = 4x + 1 + 2x + 3 + 9
= 6x + 13
= 6(2) + 13
= 12 + 13
= 25