Use the commutative property of multipli ation to write a related num er sentene 4x5=20

The Orchard Cafe has found that about 15% of the diners who make reservations don't show up. If 77 reservations have been made,

taurus [48]

Answer:

65 dinners are expected to show up

The standard deviation of the distribution is 3.13

Step-by-step explanation:

Given

Proportion = 15%

Population = 77

Required

Expected Number that'll show up

Standard Deviation

If 15% won't show up; then

100% - 15% = 85% will show up

Expected Number, E(x) of Dinner is calculated as thus;

$E(x) = np$

Where $p = 85\%$ (calculated above)

and $n = 77$

Convert p to decimal

$p = 0.85$

So;

$E(x) = 0.85 * 77$

$E(x) = 65.45$

$E(x) = 65$

65 dinners are expected to show up

Calculating Standard Deviation, SD

Standard Deviation is calculated as;

$SD = \sqrt{np(1-p)}$

Substitute 0.85 for p and 77 for n

$SD = \sqrt{77 * 0.85 * (1-0.85)}$

$SD = \sqrt{77 * 0.85 * 0.15}$

$SD = \sqrt{9.8175}$

$SD = 3.13328900678$

$SD = 3.13$ (Approximated)

The standard deviation of the distribution is 3.13

4 0

4 years ago

Write an equation of the perpendicular bisector of the segment with endpoints G 9,8       and H 3,2      .

Norma-Jean [14]

Answer:

y = -x + 11

Step-by-step explanation:

The equation of a straight line is is given by:

y = mx + b; where m is the slope and b is the y intercept

The equation of the line joining G(9, 8) and H(3, 2) is given as:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-8=\frac{2-8}{3-9}(x-9)\\\\y-8=x-9\\\\y=x-1$

The perpendicular bisector of the line joining G(9, 8) and H(3, 2) is perpendicular to the line joining G(9, 8) and H(3, 2) and passes through the midpoint of line joining G(9, 8) and H(3, 2).

Let (x, y) be the midpoint of the line joining G(9, 8) and H(3, 2). Hence:

x = (9 + 3)/2 = 6

y = (8 + 2)/2 = 5

The midpoint = (6, 5)

Two lines are perpendicular if the product of their slopes is -1.

The line joining G(9, 8) and H(3, 2) has a slope of 1, hence, the slope of the perpendicular bisector would be -1.

This means that the perpendicular bisector has a slope of -1 and passes through (6, 5). Using:

$y-y_1=m(x-x_1)\\\\y-5=-1(x-6)\\\\y-5=-x+6\\\\y=-x+11$

The equation of the perpendicular bisector is y = -x + 11

8 0

3 years ago

How do I solve for x?

NISA [10]

Write and solve an equation of ratios based upon the fact that the small and large triangles shown are similar:

5 6
---- = ---------
14 6 + x

Then 30 + 5x = 84, and 5x = 54, and so x = 54/5, or 10.8, or 10 4/5.

5 0

3 years ago

Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are

jasenka [17]

Answer:

The indicated confidence interval for the difference between the two population means is (-1.5159, 7.5159)

Step-by-step explanation:

Let the drying times of type A be the first population and the drying times of type B be the second population. Then

We have small sample sizes $n_{1} = 11$ and $n_{2} = 9$ , besides $\bar{x}_{1} = 71.5$ , $s_{1} = 3.4$ , $\bar{x}_{2} = 68.5$ and $s_{2} = 3.6$ . Therefore, the pooled

estimate is given by

$s_{p}^{2} = \frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(11-1)(3.4)^{2}+(9-1)(3.6)^{2}}{11+9-2} = 12.1822$

The 99% confidence interval for the true mean difference between the mean drying time of type A and the mean drying time of type B is given by

$(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.01/2}s_{p}\sqrt{\frac{1}{11}+\frac{1}{9}}$ , i.e.,

$(71.5-68.5)\pm t_{0.005}(3.4903)\sqrt{\frac{1}{11}+\frac{1}{9}}$

where $t_{0.005}$ is the 0.5th quantile of the t distribution with (11+9-2) = 18 degrees of freedom. So

$3\pm(-2.8784)(3.4903)(0.4495)$ , i.e.,

the indicated confidence interval for the difference between the two population means is (-1.5159, 7.5159)

5 0

3 years ago

Need #43 ‍♀️ 13 ponis

Olin [163]

The final stock price is $48.54

6 0

4 years ago

Read 2 more answers